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3 years ago

LOOK AT THE PICTURE PLEASE HELP A GIRL OUT IM STUCK ON THIS QUESTION AND I DONT HAVE A LOT OF TIME!!

Mathematics

2 answers:

marusya05 [52]3 years ago

6 0

Answer:

I think it's B.) 2x² - 2x + 2

Step-by-step explanation:

I'm not going to explain because you don't have much time.

Tomtit [17]3 years ago

3 0

Answer:

How much time do i have?

Step-by-step explanation:

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1.) Use a property to write an equivalent expression for 12*(100-5). Which property did you use?

Jlenok [28]

1. 12*100 - 12*5

You would use the distributive property to get this equation (it is equivalent to the original one)

2. Um... There's no actual story for this problem; sorry I can't solve this problem

3 0

3 years ago

Read 2 more answers

On a coordinate plane, triangle A B C is shown. Point A is at (0, 0), point B is at (3, 4), and point C is at (3, 2). What is th

Elena L [17]

Answer:

The area of triangle for the given coordinates is 1.5 $\sqrt{4.6}$

Step-by-step explanation:

Given coordinates of triangles as

A = (0,0)

B = (3,4)

C = (3,2)

So, The measure of length AB = a = $\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}$

Or, a = $\sqrt{(3-0)^{2}+(4-0)^{2}}$

Or, a = $\sqrt{9+16}$

Or, a = $\sqrt{25}$

∴ a = 5 unit

Similarly

The measure of length BC = b = $\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}$

Or, b = $\sqrt{(3-3)^{2}+(2-4)^{2}}$

Or, a = $\sqrt{0+4}$

Or, b = $\sqrt{4}$

∴ b = 2 unit

And

So, The measure of length CA = c = $\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}$

Or, c = $\sqrt{(3-0)^{2}+(2-0)^{2}}$

Or, c = $\sqrt{9+4}$

Or, c = $\sqrt{13}$

∴ c = $\sqrt{13}$ unit

Now, area of Triangle written as , from Heron's formula

A = $\sqrt{s\times (s-a)\times (s-b)\times (s-c)}$

and s = $\frac{a+b+c}{2}$

I.e s = $\frac{5+2+\sqrt{13}}{2}$

Or. s = $\frac{7+\sqrt{13}}{2}$

So, A = $\sqrt{(\frac{(7+\sqrt{13})}{2})\times ((\frac{(7+\sqrt{13})}{2})-5)\times (\frac{7+\sqrt{13}}{2}-2)\times (\frac{7+\sqrt{13}}{2}-\sqrt{13})}$

Or, A = $\sqrt{(\frac{(7+\sqrt{13})}{2})\times (\frac{(\sqrt{13}-3)}{2})\times (\frac{4+\sqrt{13}}{2})\times (\frac{7-\sqrt{13}}{2})}$

Or, A = $\frac{3}{2}$ × $\sqrt{1+\sqrt{13} }$

∴ Area of triangle = 1.5 $\sqrt{4.6}$

Hence The area of triangle for the given coordinates is 1.5 $\sqrt{4.6}$ Answer

7 0

3 years ago

Read 2 more answers

A circle that has a center at the point (3, -2) with a radius of 6. Write an equation for the circle.

crimeas [40]

Answer:

(x – 3)^2+ (y +2)^2 = 36

Step-by-step explanation:

Given data

The formula for the equation of a circle is (x – h)2+ (y – k)2 = r^2,

where (h, k) represents the coordinates of the center of the circle

h=3

k=-2

r= 6

Substitute

(x – 3)^2+ (y – (-2))^2 = 6^2

(x – 3)^2+ (y +2)^2 = 36

Hence the expression for the equation of the circle is

(x – 3)^2+ (y +2)^2 = 36

5 0

3 years ago

(-8, -1) slope = -3/4

babunello [35]

Answer:

y=-3/4x - 7

Step-by-step explanation:

When finding the slope given a point and a slope, we do the following.

y=mx+b (Slope-intercept Form)

m is the slope and x,y are the points

Plug in everything

-1= -3/4(-8)+b

Multiply

-1 = 6 + b

-7 = b

This gives us the final equation of y=-3/4x - 7

7 0

3 years ago

Find a formula for the nth term in this arithmetic sequence first term -2 common difference an=

malfutka [58]

The formula for the problem is: An = 8(n-1) - 2

3 0

1 year ago