Use a system of equations
C+P=1132
3P=C
Substitute C in first equation as
3P+P=1132
Simplify
4P=1132
Solve
P=1132/4
P=283
NOW SOLVE FOR C SUBSTITUTING P VALUE IN FIRST EQUATION
C+283=1132
C=1132-283
C=849
Printer = 283$
Computer = 849$
The Quadrilateral ABCD with coordinates (3, 1), (4, 4), (7, 5), (6, 2) is a rhombus because its length and width are both square root of 10 units and adjacent sides are not perpendicular. This can be seen by plotting the points you can either plot it or by using programs.
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Answer:
Step-by-step explanation:
Hello, as alpha and beta are zeroes of
it means that their sum is alpha+beta=1 and their product alpha*beta=-2.
The polynomial whose zeroes are 2 alpha + 1 and 2 beta + 1, means that the sum of its zeroes is 2(alpha+beta)+2=2+2=4
and the product is (2alpha+1)(2beta+1)=4 alpha*beta + 2(alpha+beta) + 1 = 4 * (-2) + 2*(1) +1 = -8 + 2 + 1 = -5. so one of these polynomials is
Thank you.
Answer:
6/25
Step-by-step explanation:
its a probability out of all the odd numbers such as 1,3,5,7,9,11,13,15,17,19,21,23,25
Answer:
x = 2
Step-by-step explanation:
Step 1 :
Equation at the end of step 1 :
(4+(4•(x-2)))-(2•(x+1)-x) = 0
Step 2 :
Equation at the end of step 2 :
(4 + 4 • (x - 2)) - (x + 2) = 0
Step 3 :
Step 4 :
Pulling out like terms :
4.1 Pull out like factors :
3x - 6 = 3 • (x - 2)
Equation at the end of step 4 :
3 • (x - 2) = 0
Step 5 :
Equations which are never true :
5.1 Solve : 3 = 0
This equation has no solution.
A a non-zero constant never equals zero.
Solving a Single Variable Equation :
5.2 Solve : x-2 = 0
Add 2 to both sides of the equation :
x = 2
One solution was found :
x = 2
Processing ends successfully
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