All categories

3 years ago

Dividing with remainders

Mathematics

1 answer:

mojhsa [17]3 years ago

8 0

Answer:

im not sure but i think 3

Step-by-step explanation:

You might be interested in

Is number 2 a x or y intercept

balu736 [363]

Hello there!

Number 2 certainly isn't an x or y intercept since it isn't meeting with any axis, however, it is the vertex of the parabola as shown in the graph.

7 0

3 years ago

A test consists of 10 multiple choice questions, each with five possible answers, one ofwhich is correct. To pass the test a stu

const2013 [10]

Answer:

40%-50%

Step-by-step explanation:

Because they are guessing and might fail half of the test or more.

I hope this helps

7 0

3 years ago

Use three different values of n to demonstrate that 2n + 3n is equivalent to 5n.

GarryVolchara [31]

n can be 0 so 2(0) +3(0) = 0 now lets go up by one so 2(1) +3(1)= 5 now we will go up another number so lets go for 2(2)= 10 so we figured out that 2(1) +3(1) is 5 so n equals 1

4 0

3 years ago

Find a power series for the function, centered at c. g(x) = 4x x2 2x − 3 , c = 0

BartSMP [9]

The power series for given function $g(x)=\frac{4x}{(x-1)(x+3)}$ is $g(x)=\sum{_{n=0}^\infty}~x^n(-1+(-\frac{x}{3} )^n)$

For given question,

We have been given a function g(x) = 4x / (x² + 2x - 3)

We need to find a power series for the function, centered at c, for c = 0.

First we factorize the denominator of function g(x), we have:

$\Rightarrow g(x)=\frac{4x}{(x-1)(x+3)}$

We can write g(x) as,

$\Rightarrow g(x)=\frac{1}{x-1}+\frac{3}{x+3}\\\\\Rightarrow g(x)=\frac{-1}{1-x}+\frac{1}{1+\frac{x}{3} }\\\\\Rightarrow g(x)=\frac{-1}{1-x}+\frac{1}{1-(-\frac{x}{3} )}\\$

We know that, $\frac{1}{1-x}=\sum{_{n=0}^\infty}~{x^n}$ if |x| < 1

and $\frac{1}{1-(-\frac{x}{3} )}=\sum{_{n=0}^\infty}~x^n(-\frac{x}{3} )^n$ if $|\frac{x}{6}| < 1$

$\Rightarrow g(x)=-\sum{_{n=0}^\infty}~x^n+\sum{_{n=0}^\infty}~x^n(-\frac{x}{3} )^n\\$ if |x| < 1 and if $|\frac{x}{6}| < 1$

$\Rightarrow g(x)=\sum{_{n=0}^\infty}~x^n(-1+(-\frac{x}{3} )^n)$ if |x| < 1

Therefore, the power series for given function $g(x)=\frac{4x}{(x-1)(x+3)}$ is $g(x)=\sum{_{n=0}^\infty}~x^n(-1+(-\frac{x}{3} )^n)$

Learn more about the power series here:

brainly.com/question/11606956

#SPJ4

5 0

2 years ago

What is the congruence correspondence, if any, that will prove the given triangles congruent?

ladessa [460]

Answer:

C. HL

Step-by-step explanation:

The two triangles shown are right triangles.

The hypotenuse of one is congruent to the hypotenuse of the other. Also, the length of one of the legs of one triangle is congruent to the corresponding leg of the other triangle.

Based on true HL Congruence theorem, both triangles are congruent to each other.

Therefore, the congruence correspondence that will prove both triangles are congruent is: HL

5 0

2 years ago