The perimeter is the sides of the hexagon. One of the hexagon edges is shared with a rectangular face. Solve for that edge. 78/6=13. The height is the length and edge is the width. Area is length(16) times width(13). 16•13=208. The answer is 208mm^2
7.) Area of a square pyramid is given by A = s^2 + 2sl; where s is the side length of the base and l is the slant height.
Area of given pyramid = 4^2 + (2 x 4 x 7) = 16 + 56 = 72 ft^2
8.) Area of the given pyramid is the area of the hexagonal base plus the area of the six slant triangles.
Area of hexagonal base = (3sqrt(3))/2 x 10^2 = 150 x 1.732 = 259.8
Area of the 6 traingles = 6(1/2 x 10 x 13) = 6 x 65 = 390
Total surface area of the pyramid = 259.8 + 390 = 649.8 ≈ 650 m^2
9.) Using pythagoras rule, the slant height is sqrt(6^2 + 3.5^2) = sqrt(36 + 12.25) = sqrt(48.25) = 6.9 mm
10.) The surface area of a cone is given by πr^2 + πrl
Area = π x 6^2 + π x 6 x 20 = 36π + 120π = 490.1 cm^2
11.) l = sqrt(r^2 + h^2) = sqrt(11^2 + 16^2) = sqrt(121 + 256) = sqrt(377) = 19m
The statement that is best supported by the data in the stem and leaf plot is D. The most common number of items sold is 15.
<h3>How to illustrate the information?</h3>
It should be noted that the stem and plot diagram is important to illustrate the data given.
Based on the information given, the most common number of items sold is 15.
In conclusion, the correct option is D.
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The total number of items sold by each student who participated in a fund-raiser is shown in the stem and leaf plot.
Which statement is best supported by the data in the stem and leaf plot?
The number of students who sold between 10 and 20 items is greater than the number of students who sold more then 40 items.
The number of students who sold more than 30 items is greater than the number of students who sold fewer than 30 items.
The most common number of items sold is 30.
The most common number of items sold is 15.
Answer:
327.21 euros.
Step-by-step explanation: