It is D you have subtract them
I think the answer is 3/2 but i am not sure
Answer:
<u><em>x>2</em></u>
Step-by-step explanation:
<u><em>x3+3x2=7x+6</em></u>
<u><em>x3+3x2−(7x+6)=7x+6−(7x+6)</em></u>
<u><em>x3+3x2−7x−6=0</em></u>
<u><em>(x−2)(x2+5x+3)=0</em></u>
<u><em>x−2=0 or x2+5x+3=0</em></u>
<u><em>x=2 or x=−0.6972243622680054 or x=−4.302775637731995</em></u>
<u><em>x<−4.302776</em></u>
<u><em>−4.302776<x<−0.697224</em></u>
<u><em>−0.697224<x<2</em></u>
<u><em>x>2(Works in original inequality)</em></u>
Standard deviation is: It is a measure of how spread out numbers are. It is the square root of the Variance, and the Variance is the average of the squared differences from the Mean.
For example: To find the standard deviation, you have to add up all the numbers in the data set, then divide by how many numbers there are, and that will get you your answer.
Example, Say your data set is: 9, 2, 5, 4, 12, 7, 8, 11, 9, 3, 7, 4, 12, 5, 4, 10, 9, 6, 9, 4.
The Mean is: 9 + 2 + 5 + 4 + 12 + 7 + 8 + 11 + 9 + 3 + 7 + 4 + 12 + 5 + 4 + 10+ 9 + 6 + 9 + 4. Over 20. That equals: 104 over 20 = 7.
So, the Standard Variance and Mean is: 7 for this problem.
Hope I helped!
- Debbie
Answer:
y=27 when x=2
Step-by-step explanation:
y varies inversely as the cube of x
y=k(1/X^3)
y=1 when x=6
y=k(1/X^3)
1=k(1/6^3)
1=k(1/216)
k=1÷1/216
K=1×216/1
k=216
find y when x=2
y=k(1/X^3)
y=216(1/2^3)
y=216(1/8)
y=216/8
y=27
