Boyle's law p1V1=p2V2
p2=(p1V1)/V2
p2=(205*10^3 Pa * 4*10^-3 m^3 ) / (12*10^-3 m^3)
p2= 68333 Pa
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Answer:
K = 0.5
Explanation:
Based on the reaction:
PCl₃ + Cl₂ ⇄ PCl₅
The equilibrium constant, K, is defined as:
K = P PCl₅ / P PCl₃ * P Cl₂
<em>Where P represent the pressure at the equilibrium for each one of the gases involved in the equilibrium.</em>
<em />
As:
P PCl₅ = 1.0atm
P PCl₃ = 1.0atm
P Cl₂ = 2.0atm
K = 1.0atm / 1.0atm * 2.0atm
<h3>K = 0.5</h3>
Answer:
B
Explanation:
First of all it is important to know that a half filled orbital is particularly stable. In phosphorus all the electrons occur singly in the 3p sublevel minimizing inter electronic repulsion hence it is more difficult to remove an electron from this energetically stable arrangement. In sulphur, electrons are paired in one of the 3p orbitals thereby lowering the energy of that level due to instability caused by interelectronic repulsion between two electrons in the same orbital.
If the ion is negatively charged, anion, it means that it gains two
electrons from its surroundings. The number of electrons of an argon (neutral
atom) is 18. Two of the electrons in our anion is from the surrounding, so
originally it only has 16 electrons.
In the periodic table, the 16th element is sulphur. The
chemical symbol of sulphur is S. Thus, the anion is the negatively charged
sulphur with chemical symbol of S2-.
