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ivanzaharov [21]

1 year ago

14

Chromium has four naturally occurring isotopes. cr-50 (mass of 49.946 amu and 4.35% abundance); cr-52 (mass of 51.941 amu and 83

.79% abundance); cr-53 (mass of 52.941 amu and 9.50% abundance); and cr-54 (mass of 53.939 amu and 2.36% adundance). calculate the average atomic mass of chromium to 3 decimal points. average atomic mass=(mass a)(%a) (mass b)(%b) (mass c)(%c) (mass d)(%d) 100

1 answer:

satela [25.4K]1 year ago

3 0

The average atomic mass of chromium to 3 decimal points is 52. 055 g. mol.

<h3>What is the average atomic mass?</h3>

"The weighted average mass of the atoms in a naturally occurring sample of an element is the average atomic mass, also known as atomic weight."

Given the different isotopes of chromium.

The four isotopes of chromium are cr-50, cr-52, cr-53 cr-54.

The average atomic mass will be

Let us take the weighted average of your isotopes:

50 × 0.0434 + 52 × 0.8379 + 53 × 0.095 + 54 × 0.0237 = 52. 055 g.

Thus, the average atomic mass of chromium is 52. 055 g.

To learn more about average atomic mass, refer to the link:

brainly.com/question/13753702

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3 years ago

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What volume of 0.152 M KMnO4 solution would completely react with 20.0 mL of 0.381 M FeSO4 solution according to the following n

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<u>Answer:</u> The volume of permanganate ion (potassium permanganate) is 10.0 mL

<u>Explanation:</u>

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$ .....(1)

Molarity of ferrous sulfate solution = 0.381 M

Volume of solution = 20.0 mL = 0.020 L (Conversion factor: 1 L = 1000 mL)

Putting values in equation 1, we get:

$0.381M=\frac{\text{Moles of ferrous sulfate}}{0.020L}\\\\\text{Moles of ferrous sulfate}=(0.381mol/L\times 0.020L)=0.00762mol$

For the given chemical equation:

$5Fe^{2+}+8H^++MnO_4^-\rightarrow 5Fe^{3+}+Mn^{2+}+4H_2O$

By Stoichiometry of the reaction:

5 moles of iron (II) ions (ferrous sulfate) reacts with 1 mole of permanganate ion (potassium permanganate)

So, 0.00762 moles of iron (II) ions (ferrous sulfate) will react with = $\frac{1}{5}\times 0.00762=0.00152mol$ of permanganate ion (potassium permanganate)

Now, calculating the volume of permanganate ion (potassium permanganate) by using equation 1, we get:

Molarity of permanganate ion (potassium permanganate) = 0.152 M

Moles of permanganate ion (potassium permanganate) = 0.00152 mol

Putting values in equation 1, we get:

$0.152mol/L=\frac{0.00152mol}{\text{Volume of permanganate ion (potassium permanganate)}}\\\\\text{Volume of permanganate ion (potassium permanganate)}=\frac{0.00152mol}{0.152mol/L}=0.01L=10.0mL$

Hence, the volume of permanganate ion (potassium permanganate) is 10.0 mL

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3 years ago

A solution containing 0.102 g of an unknown compound dissolved in 100. mL of water has an osmotic pressure of 28.1 mmHg at 20.°C

IrinaVladis [17]

Answer:

MM = 680g / mol

Explanation:

Hello! To calculate the molar mass of the compound (g / mol), I first have to calculate the molarity.

Molarity can be calculated from the osmotic pressure equation.

op = M * R * T

op = osmotic pressure = 28.1mmHg * (1 atm / 760mmHg) = 0.037atm

M = molarity

R = gas constant

T = temperature (K) = 20 ° C + 273.15 = 293.15K

M (mol / L) = op / R * T

M = 0.037atm / ((0.082 (atm * L) / (K * mol)) * 293.15K) = 0.0015mol / L

As I have the volume = 100ml * (1L / 1000ml) = 0.1L

I can calculate the amount of moles

n = M * V = 0.0015 * 0.1 = 0.00015mol

n = m / MM

m = mass

MM = molar mass

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MM = 680g / mol

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