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ivanzaharov [21]
2 years ago
14

Chromium has four naturally occurring isotopes. cr-50 (mass of 49.946 amu and 4.35% abundance); cr-52 (mass of 51.941 amu and 83

.79% abundance); cr-53 (mass of 52.941 amu and 9.50% abundance); and cr-54 (mass of 53.939 amu and 2.36% adundance). calculate the average atomic mass of chromium to 3 decimal points. average atomic mass=(mass a)(%a) (mass b)(%b) (mass c)(%c) (mass d)(%d) 100
Chemistry
1 answer:
satela [25.4K]2 years ago
3 0

The average atomic mass of chromium to 3 decimal points is 52. 055 g. mol.

<h3>What is the average atomic mass?</h3>

"The weighted average mass of the atoms in a naturally occurring sample of an element is the average atomic mass, also known as atomic weight."

Given the different isotopes of chromium.

The four isotopes of chromium are cr-50, cr-52, cr-53 cr-54.

The average atomic mass will be

Let us take the weighted average of your isotopes:

50 × 0.0434 + 52 × 0.8379 + 53 × 0.095 + 54 × 0.0237 = 52. 055 g.

Thus, the average atomic mass of chromium is 52. 055 g.

To learn more about average atomic mass, refer to the link:

brainly.com/question/13753702

#SPJ4

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200.0 mL of 3.85 M HCl is added to 100.0 mL of 4.6 M barium hydroxide. The reaction goes to completion. What is the concentratio
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Answer:

2.387 mol/L

Explanation:

The reaction that takes place is:

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First we <u>calculate how many moles of each reagent were added</u>:

  • HCl ⇒ 200.0 mL * 3.85 M = 203.85 mmol HCl
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460 mmol of Ba(OH)₂ would react completely with (2*460) 920 mmol of HCl. There are not as many mmoles of HCl so Ba(OH)₂ will remain in excess.

Now we <u>calculate how many moles of Ba(OH)₂ reacted</u>, by c<em>onverting the total number of HCl moles to Ba(OH)₂ moles</em>:

  • 203.85 mmol HCl * \frac{1mmolBa(OH)_{2}}{2mmolHCl}= 101.925 mmol Ba(OH)₂

This means the remaining Ba(OH)₂ is:

  • 460 mmol - 101.925 mmol = 358.075 mmoles Ba(OH)₂

There are two OH⁻ moles per Ba(OH)₂ mol:

  • OH⁻ moles = 2 * 358.075 = 716.15 mmol OH⁻

Finally we <u>divide the number of OH⁻ moles by the </u><u><em>total</em></u><u> volume</u> (100 mL + 200 mL):

  • 716.15 mmol OH⁻ / 300.0 mL = 2.387 M

So the answer is 2.387 mol/L

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<span>
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