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laiz [17]
3 years ago
14

JOURNAL 5.3.4. PLZZZ HELP, I NEED 1-9

Mathematics
1 answer:
aniked [119]3 years ago
7 0

Answer:

8?

Step-by-step explanation:

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to arrive at 2000 liters of 60% saline solution the attendant has to mix a 90% and a 40% saline solution. How many liters of eac
CaHeK987 [17]

Answer:

<u>800 liters</u> of 90% saline solution and <u>1200 liters</u> of 40% saline solution should be used.

Step-by-step explanation:

Given:

At 2000 liters of 60% saline solution the attendant has to mix a 90% and a 40% saline solution.

Now, to find the number of liters of saline solution each should be used.

<u><em>Let the liters of 90% saline solution mix be </em></u>x.<u><em /></u>

<u><em>And let the liters of 40% saline solution mix be</em></u> y.

So, the total number of liters:

x+y=2000.

y=2000-x\ \ \ ....(1)

Now, the total percentage of saline solution:

90\%\ of\ x+40\%\ of\ y=60\%\ of\ 2000

\frac{90}{100}\times x+\frac{40}{100}\times y=\frac{60}{100}\times 2000

0.9x+0.4y=1200

Substituting the value of y from equation (1) we get:

0.9x+0.4(2000-x)=1200

0.9x+800-0.4x=1200

0.5x+800=1200

Subtracting both sides by 800 we get:

0.5x=400

Dividing both sides by 0.5 we get:

x=800.

<u>The liters of 90% saline solution mix = 800.</u>

Now, substituting the value of x in equation (1) to get the liters of 40% saline solution:

y=2000-x

y=2000-800

y=1200.

<u>Thus, the liters of 40% saline solution = 1200.</u>

Therefore, 800 liters of 90% saline solution and 1200 liters of 40% saline solution should be used.

8 0
3 years ago
Pure copper was mixed with a 10% copper alloy to produce an alloy thát was 25% copper. How much of the pure copper and how much
lora16 [44]

Answer:

6kg pure copper and 30 kg 10% copper was mixed to give 36kg of 25% alloy

Step-by-step explanation:

Here, we want to produce 36 kg of 25% alloy

Let the Pure copper be x kg while 10% alloy be y kg

Pure copper is simply 100% copper

Thus;

x + y = 36 •••••(i)

Then;

100% of x + 10% of y = 25% of 36

= x + 0.1y = 9 •••••• ii)

From i x = 36-y

from ii, x = 9-0.1y

Equate both x

36-y = 9-0.1y

36-9 = 0.1y + y

0.9y = 27

y = 27/0.9

y = 30

x = 36-y

x = 36-30

x = 6 kg

8 0
3 years ago
7th grade math help me pleasee :))
natima [27]
It’s the first one -13–16
3 0
3 years ago
5 x {3 x [9 - (4 + 1)]} + 20 ÷ 4 x 2 =
adell [148]
To solve a problem like this, we need to start with the innermost parenthesis. Doing that, we get to 4+1, evaluating it giving us 5. This turns our expression into 5 x {3 x [9 - 5]} + 20 ÷ 4 x 2.



Now, the innermost parenthesis is 9-5. Evaluating that gives us 4. Our expression is now 5 x {3 x 4} + 20 ÷ 4 x 2.



Once again, we go to the innermost parenthesis and evaluate whatever is there. This turns our expression into <span>5 x 12 + 20 ÷ 4 x 2.



Now, we can simply use order of operations to compute that the value of the expression is equal to 70. </span>
7 0
3 years ago
Read 2 more answers
Mathhhhhhhhhhhhhhhhhh
xxTIMURxx [149]

Answer:

formal proof

Step-by-step explanation:

https://quizlet.com/230868297/geometry-u2-review-flash-cards/

7 0
3 years ago
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