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zloy xaker [14]
3 years ago
10

Can somelne help me ​

Mathematics
2 answers:
serg [7]3 years ago
3 0

Answer:

2

Step-by-step explanation:

goblinko [34]3 years ago
3 0

Answer:

9×(10-5)-31)÷7

9×5-31÷7

45-31÷7

14÷7

2

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Tyrell has a bankruptcy on his credit report and therefore pays higher interest rates on his current loans. he calculates that t
vova2212 [387]

Based on the simple interest amount he could be making, and the rate of investment, Tyrell's additional interest per month is $1,000.

<h3>How much is Tyrell paying in additional interest?</h3>

Assuming the additional interest that Tyrell is paying is x, the following formula can be used:

300 = (x × 2.5%) x 12 months

Solving gives:

300 = 0.025x × 12

0.025x = 300/12

x = 25 / 0.025

x = $1,000

Find out more on additional interest at brainly.com/question/27037531.

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3 years ago

Grace [21]

Answer:

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How old is david if his age 6 years from now will be twice his age 7 years ago?
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8 0
4 years ago
Read 2 more answers
The vertex of this parabola is at (2,-1) when the y value is 0 and then x value is 5 what is the coefficient of the squared term
Darina [25.2K]

\bf ~~~~~~\textit{parabola vertex form} \\\\ \begin{array}{llll} \stackrel{\textit{we'll use this one}}{y=a(x- h)^2+ k}\\\\ x=a(y- k)^2+ h \end{array} \qquad\qquad vertex~~(\stackrel{2}{ h},\stackrel{-1}{ k}) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \begin{cases} h=2\\ k=-1 \end{cases}\implies y=a(x-2)^2-1 \\\\\\ \textit{we also know that } \begin{cases} y=0\\ x=5 \end{cases}\implies 0=a(5-2)^2-1\implies 1=9a \\\\\\ \cfrac{1}{9}=a\qquad therefore\qquad \boxed{y=\cfrac{1}{9}(x-2)^2-1}


now, let's expand the squared term to get the standard form of the quadratic.


\bf y=\cfrac{1}{9}(x-2)^2-1\implies y=\cfrac{1}{9}(x^2-4x+4)-1 \\\\\\ y=\cfrac{1}{9}x^2-\cfrac{4}{9}x+\cfrac{4}{9}-1\implies \stackrel{its~coefficient}{y=\stackrel{\downarrow }{\cfrac{1}{9}}x^2-\cfrac{4}{9}x-\cfrac{5}{9}}

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3 years ago
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