A role-playing game uses an 11-sided die that displays the numbers 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11 What is the probability tha
kondor19780726 [428]
Using it's concept, it is found that there is a 27.3% probability that someone throws the 11-sided die one time and rolls a number 9 or higher.
<h3>What is a probability?</h3>
A probability is given by the <u>number of desired outcomes divided by the number of total outcomes</u>.
In this problem, there are 11 numbers, 3 of which are 9 or higher, hence the probability is:
p = 3/11 = 0.273 = 27.3%.
More can be learned about probabilities at brainly.com/question/14398287
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Answer:
DNE
do not exist
Step-by-step explanation:
There is no common factor at all
8 equals 2,4,1,8
11 just equals 1,11
Answer:
2.5 mile inch 158400
Step-by-step explanation:
It's on google
The answer is 867.
3^3 = 27
27•32 + 12/4
864 + 3 = 867
