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2 years ago

Negative one and one-sixth divided by negative six

Mathematics

2 answers:

Sveta_85 [38]2 years ago

5 0

Answer:

Step-by-step explanation:

kozerog [31]2 years ago

4 0

Answer: -13.714

Step-by-step explanation:

You might be interested in

Where did we get one?

77julia77 [94]

Answer:

The -1 came from factoring.

The equation is multiplied by 8 because 8 could be pulled from 16x-8.

16 can be divided by 8 2 times and 8 can only divided by 8 once.

so factoring it makes the equation 8(2x-1)

5 0

2 years ago

A lion’s heart beats 12 times in 16 seconds.how many heartbeats will it have in 60 seconds?

Sergio [31]

Hey there!

Here is your answer:

The proper answer to this question is "44 times".

Reason:

You have to solve it this way:

12 heartbeats=16 seconds

16+16=32
36+16=48
48+16=64
16-12=4
12+12=36+8=44

Therefore lions heart beats 44 times every 60 seconds.

If you need anymore help feel free to ask me!

Hope this helps!

~Nonportrit

6 0

3 years ago

If a,b,c are all non-zero numbers and a+b+c=0, prove that

Butoxors [25]

Given - a+b+c = 0

To prove that- 

a²/bc + b²/ac + c²/ab = 3

Now we know that

when x+y+z = 0,

then x³+y³+z³ = 3xyz

that means

 (x³+y³+z³)/xyz = 3 ---- eq 1)

Lets solve for LHS

LHS = a²/bc + b²/ac + c²/ab

we can write it as LHS = a³/abc + b³/abc + c³/abc

by multiplying missing denominators,

now take common abc from denominator and you'll get,

LHS = (a³+b³+c³)/abc --- eq (2)

Comparing one and two we can say that

(a³+b³+c³)/abc = 3

Hence proved,

a²/bc + b²/ac + c²/ab = 3

6 0

2 years ago

According to government data, 20% of employed women have never been married. If 10 employed women are selected at random, what i

Ierofanga [76]

Answer:

a) $P(X=2) = (10C2) (0.2)^2 (1-0.2)^{10-2}= 0.302$

b) $P(X\leq 2) = P(X=0) + P(X=1) +P(X=2)$

$P(X=0) = (10C0) (0.2)^0 (1-0.2)^{10-0}= 0.107$

$P(X=1) = (10C1) (0.2)^1 (1-0.2)^{10-1}= 0.268$

$P(X=2) = (10C2) (0.2)^2 (1-0.2)^{10-2}= 0.302$

And replacing we got:

$P(X\leq 2) = 0.107+0.268+0.302=0.678$

c) For this case we want this probability:

$P(X\geq 8) = P(X=8) + P(X=9) +P(X=10)$

But for this case the probability of success is p =1-0.2= 0.8

We can find the individual probabilities and we got:

$P(X=8) = (10C8) (0.8)^8 (1-0.8)^{10-8} =0.302$

$P(X=9) = (10C9) (0.8)^9 (1-0.8)^{10-9} =0.268$

$P(X=10) = (10C10) (0.8)^{10} (1-0.8)^{10-10} =0.107$

And replacing we got:

$P(X \geq 8) = 0.677$

And replacing we got:

$P(X\geq 8)=0.0000779$

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Let X the random variable of interest, on this case we now that:

$X \sim Bin (n=10 ,p=0.2)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

Solution to the problem

Let X the random variable "number of women that have never been married" , on this case we now that the distribution of the random variable is:

$X \sim Binom(n=10, p=0.2)$

Part a

We want to find this probability:

$P(X=2)$

And using the probability mass function we got:

$P(X=2) = (10C2) (0.2)^2 (1-0.2)^{10-2}= 0.302$

Part b

For this case we want this probability:

$P(X\leq 2) = P(X=0) + P(X=1) +P(X=2)$

We can find the individual probabilities and we got:

$P(X=0) = (10C0) (0.2)^0 (1-0.2)^{10-0}= 0.107$

$P(X=1) = (10C1) (0.2)^1 (1-0.2)^{10-1}= 0.268$

$P(X=2) = (10C2) (0.2)^2 (1-0.2)^{10-2}= 0.302$

And replacing we got:

$P(X\leq 2) = 0.107+0.268+0.302=0.678$

Part c

For this case we want this probability:

$P(X\geq 8) = P(X=8) + P(X=9) +P(X=10)$

But for this case the probability of success is p =1-0.2= 0.8

We can find the individual probabilities and we got:

$P(X=8) = (10C8) (0.8)^8 (1-0.8)^{10-8} =0.302$

$P(X=9) = (10C9) (0.8)^9 (1-0.8)^{10-9} =0.268$

$P(X=10) = (10C10) (0.8)^{10} (1-0.8)^{10-10} =0.107$

And replacing we got:

$P(X \geq 8) = 0.677$

3 0

3 years ago

Solve for x: 4.23x + 1 = 17.8929 A. 0 B. 14.6629 C. 5.23 D. 6.23 PLEASE HELP!!!

maksim [4K]

Answer:

Step-by-step explanation:

6 0

2 years ago