Top half:
D (x-2, y+3) E (x-3, y(+\-) 0) F (x+1, y-2)
P (x+1, y+2) Q (x+3, y+4) R (x+5, y+2)
Distance stretched = 0.4 * 124 = 49.6 cms
converting to meters we divide by 100:-
Answer is 0.496 meters
Answer:
(-5/3, -4/3)
Step-by-step explanation:
3 < 6c +13 < 5 . . . . given
-10 < 6c < -8 . . . . . subtract 13
-10/6 < c < -8/6 . . . divide by 6
We can express the interval using reduced fractions as ...
(-5/3, -4/3)
