- The slope of the graph of the function is equal to 0 for x between x = -3 and x = -2.
- The slope of the graph of the function is equal to 0 for x between x = 3 and x = 4.
- The greatest value of y is y = 4.
- The smallest value of y is y = -3.
<h3>How to complete the sentences?</h3>
By critically observing the graph shown in the image attached below, we can logically deduce that the slope of the graph of this function is equal to 0 for x, between x = -3 and x = -2.
Similarly, the slope of the graph of this function is also equal to 0 for x, between x = 3 and x = 4.
Based on the graph (see attachment), the greatest value of y is 4 while the smallest value of y is -3.
Read more on slope here: brainly.com/question/3493733
#SPJ1
Given the center 
and the radius 
of a circle, its equation is
In your case, the center is (-4,0), and the radius is 2. Plug these values into the generic formula and you'll get the equation.
We will need to have two equations here, having x as the missing length. We know that the chairs are in the same amount on each occasion, so each equation should be equal to the other.
This sets up a problem of:
6x + 7 = 4x + 13
7 and 13 being the leftover chairs and 6 and 4 being the rows. Let’s solve for x.
x = 3
Knowing this, we plug in x for one of the equations
6(3) + 7
18 + 7
25
Liam has 25 chairs.
4 x 5 x 5 is 100 if u distribute
Now 5 + 5 x 4 is 25
Answer:
P = 6200 / (1 + 5.2e^(0.0013t))
increases the fastest
Step-by-step explanation:
dP/dt = 0.0013 P (1 − P/6200)
Separate the variables.
dP / [P (1 − P/6200)] = 0.0013 dt
Multiply the left side by 6200 / 6200.
6200 dP / [P (6200 − P)] = 0.0013 dt
Factor P from the denominator.
6200 dP / [P² (6200/P − 1)] = 0.0013 dt
(6200/P²) dP / (6200/P − 1) = 0.0013 dt
Integrate.
ln│6200/P − 1│= 0.0013t + C
Solve for P.
6200/P − 1 = Ce^(0.0013t)
6200/P = 1 + Ce^(0.0013t)
P = 6200 / (1 + Ce^(0.0013t))
At t = 0, P = 1000.
1000 = 6200 / (1 + C)
1 + C = 6.2
C = 5.2
P = 6200 / (1 + 5.2e^(0.0013t))
You need to change the exponent from negative to positive.
The inflection points are where the population increases the fastest.
