598,909 is the answer because when I put that for a test I got it right
1-r=-5
add r to both sides so the one side cancels out, then it should be 1=r-5
then you add -5 on each sides (because what you do to one side you must do to the other) and it would then have r on its own side which would give you your answer of r=6. To check 1-6 does equal -5
Answer:
20 Units
Step-by-step explanation:
Hight times length/by half is tribular prism Formula
Solving for the polynomial function of least degree with
integral coefficients whose zeros are -5, 3i
We have:
x = -5
Then x + 5 = 0
Therefore one of the factors of the polynomial function is
(x + 5)
Also, we have:
x = 3i
Which can be rewritten as:
x = Sqrt(-9)
Square both sides of the equation:
x^2 = -9
x^2 + 9 = 0
Therefore one of the factors of the polynomial function is (x^2
+ 9)
The polynomial function has factors: (x + 5)(x^2 + 9)
= x(x^2 + 9) + 5(x^2 + 9)
= x^3 + 9x + 5x^2 = 45
Therefore, x^3 + 5x^2 + 9x – 45 = 0
f(x) = x^3 + 5x^2 + 9x – 45
The polynomial function of least degree with integral coefficients
that has the given zeros, -5, 3i is f(x) = x^3 + 5x^2 + 9x – 45
30 minutes because you would have to wait until one machine finishes
