Answer:
There is more than one codon that can specify most amino acids, therefore you never know which one was used for a particular protein, unless you can look at the DNA or RNA sequence.
Simply put it could die off by not being able to compete with native species for resources. Or it could out compete the native species.
Answer:
WILD TYPE= 425;
TAN-BARE= 425;
TAN= 75;
BARE= 75
Explanation:
Fifteen map units apart implies that 15% of the offspring are products of recombination.
Out of 1000 offsprings, therefore 15% of 1000= 0.15 × 1000=150
150 offsprings are products of recombination.
100-15 =85%
Therefore, 85% of the offspring are parental.
So, if tan-bodied, ware-winged female was mated with wild-type male resulting in F1 phenotypically wild-type females were mated to tan-bodied, bare-winged males.
The expected number of offsprings that are tanned but have normal wings would be:
Wild type= 50% of 850
0.50 × 850 = 425
Tan-bare= 50% of 850
0.50 × 850 = 425
tan= 50% of 150
0.50×150= 75
Bare= 50% of 150
0.50×150=75
<span>This is due to the higher forces needed to pump blood through the systemic circuit (around the body) compared to the pulmonary circuit.</span>
A front that spirals counterclockwise in the northern Hemisphere is called a cyclone.