R=$350, I=0.05, n=15
A = 350 (1+0.05)^15 = 350(1.05)^15 = 350 (2.0789)=727.62 <- Answer
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You didn't provide the "given point", but I assume you're capable of plugging it in.
Considering that the p-value associated for a r<em>ight-tailed test with z = 2.115</em> is of 0.0172, it is found that it is significant at the 5% level, but not at the 1% level.
<h3>When a measure is significant?</h3>
- If p-value > significance level, the measure is not significant.
- If p-value < significance level, the measure is significant.
Using a z-distribution calculator, it is found that the p-value associated for a r<em>ight-tailed test with z = 2.115</em> is of 0.0172, hence, this is significant at the 5% level, but not at the 1% level.
More can be learned about p-values at brainly.com/question/16313918
Answer:
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Step-by-step explanation:
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