When considering similar triangles, we need congruent angles and proportional sides.
Hence
"Angles B and B' are congruent, and angles C and C' are congruent." is sufficient to prove similarity of two triangles.
"Segments AC and A'C' are congruent, and segments BC and B'C' are congruent." does not prove anything because we know nothing about the angles.
"Angle C=C', angle B=B', and segments BC and B'C' are congruent." would prove ABC is congruent to A'B'C' if and only if AB is congruent to A'B' (not just proportional).
"<span>Segment BC=B'C', segment AC=A'C', and angles B and B' are congruent</span>" is not sufficient to prove similarity nor congruence because SSA is not generally sufficient.
To conclude, the first option is sufficient to prove similarity (AAA)
Answer:
2/15
Step-by-step explanation:
P(B,B) = 4/10 x 3/9
= 2/5 x 1/3 or 2/15
The value of the expression -2xy for x = -4.7 and y = 0.2 is 1.88. Thus option number 3 is correct.
<u>Solution:</u>
We have been given an expression that is -2xy and have been asked to find its value for the given values of x and y
The given values of x and y are -4.7 and 0.2 respectively.
To find the value of the expression for the given values of x and y we substitute the values of x and y in the given expression and solve it as follows:
Given expression = -2xy

Hence the option number 3 is correct.
The x intrercepts is where the function crosses the x axis; In other words, it is where the output of the function is 0.
In a quadratic, you can start by factoring, if it’s unable to be factored then use the quadratic formula. Also, it is good to use the discriminate.
D= Discrimminate
D>0 2 real solutions
D=0 1 real solution
D<0 2 imaginary solutions.
The discrimminate is the equation/expression under the radical of the quadratic formula. With this formula, it’s not factorable. Using the discriminate it is also seen, as you’ll get a negative in the square root. This is imagenary because you cannot take the root of a negative value, which is why “i” is used to represent the square root of negative one.