All categories

3 years ago

If you help I will give you brainiest

Mathematics

1 answer:

Feliz [49]3 years ago

5 0

9514 1404 393

Answer:

5 miles

Step-by-step explanation:

It may get a bit messy, but we can solve for the desired value directly. Let d = the distance walked (in miles). Then 20-d is the distance traveled in the car. The relevant relation is ...

time = distance / speed

The total travel time is 9:00 -6:50 = 2:10 = 2 1/6 hours = 13/6 hours. Here is the equation for total travel time.

total time = time spent walking + time spent riding

13/6 = (d/3) + (20-d)/30

Multiplying by 30 gives ...

65 = 10d + 20 -d

45 = 9d . . . . . . . . . . subtract 20

5 = d . . . . . . . . . . . . divide by 9

The girl walked 5 miles.

_____

Check

Her walking time was (5 mi)/(3 mph) = 5/3 h = 1:40.

Her riding time was (15 mi)/(30 mph) = 1/2 h = 0:30.

Her total travel time was 1:40 +0:30 = 1:70 = 2:10, as required.

You might be interested in

A new bean company is working on designing its label for the can. If the can measures 4 inches in height and has a 3 inch diamet

Arlecino [84]

Answer: 37.68 square inches of paper

Step-by-step explanation:

Hi to answer this question we have to calculate the side area (since the label doesn't cover the top and bottom area)

First, we have to find the circumference.

Circumference (C) = 2 π r

Since:

Diameter = 2 radius

3 = 2r

3/2 =r

r =1.5 inches

Back with the circumference formula

Replacing with the values given:

C = 2 (3.14) 1.5

C= 9.42

Side area = C x heigth = 9.42 x 4 = 37.68 square inches

4 0

3 years ago

What is the perpendicular line slope of -2x-9y=4

zimovet [89]

The slope would be 9/2

8 0

3 years ago

Find the commission.

juin [17]

Answer:

63.9

Step-by-step explanation:

Convert 9% to a decimal: 0.09

710×.09=63.9

Please give me brainliest

3 0

3 years ago

PLEASE HELP!!!!! Find the volume of a cone that has a diameter 30ft and a height of 12ft.

Leviafan [203]

Answer:

the answer is 2827.4

Step-by-step explanation:

$\pi \: {r}^{2} \frac{h}{3}$

5 0

3 years ago

Find the area of the region enclosed by the graphs of the functions

Vaselesa [24]

Answer:

$\displaystyle A = \frac{8}{21}$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Algebra I

Terms/Coefficients
Functions
Function Notation
Graphing
Solving systems of equations

Calculus

Area - Integrals

Integration Rule [Reverse Power Rule]: $\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C$

Integration Rule [Fundamental Theorem of Calculus 1]: $\displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)$

Integration Property [Addition/Subtraction]: $\displaystyle \int {[f(x) \pm g(x)]} \, dx = \int {f(x)} \, dx \pm \int {g(x)} \, dx$

Area of a Region Formula: $\displaystyle A = \int\limits^b_a {[f(x) - g(x)]} \, dx$

Step-by-step explanation:

*Note:

Remember that for the Area of a Region, it is top function minus bottom function.

Step 1: Define

f(x) = x²

g(x) = x⁶

Bounded (Partitioned) by x-axis

Step 2: Identify Bounds of Integration

Find where the functions intersect (x-values) to determine the bounds of integration.

Simply graph the functions to see where the functions intersect (See Graph Attachment).

Interval: [-1, 1]

Lower bound: -1

Upper Bound: 1

Step 3: Find Area of Region

Integration

Substitute in variables [Area of a Region Formula]: $\displaystyle A = \int\limits^1_{-1} {[x^2 - x^6]} \, dx$
[Area] Rewrite [Integration Property - Subtraction]: $\displaystyle A = \int\limits^1_{-1} {x^2} \, dx - \int\limits^1_{-1} {x^6} \, dx$
[Area] Integrate [Integration Rule - Reverse Power Rule]: $\displaystyle A = \frac{x^3}{3} \bigg| \limit^1_{-1} - \frac{x^7}{7} \bigg| \limit^1_{-1}$
[Area] Evaluate [Integration Rule - FTC 1]: $\displaystyle A = \frac{2}{3} - \frac{2}{7}$
[Area] Subtract: $\displaystyle A = \frac{8}{21}$

Topic: AP Calculus AB/BC (Calculus I/II)

Unit: Area Under the Curve - Area of a Region (Integration)

Book: College Calculus 10e

6 0

3 years ago