Hypothenus = sqrt ((x^2 - y^2)^2 + (2xy)^2) = sqrt(x^4 - 2x^2y^2 + y^4 + 4x^2y^2) = sqrt(x^4 + 2x^2y^2 + y^4) = sqrt(x^2 + y^2)^2 = x^2 + y^2
41 is not a composite number because you can not divide 41 with any number. Therefore, it is prime.
Hi! I'm happy to help!
Our total line is JL (4x), and it is split into two parts: JK, and KL. We have our values, and we know that JK+KL=JL, so we can substitute our values and solve for x:
4x=(2x+3)+(x)
4x=3x+3
To solve for x, we have to isolate it on one side of the equation.
First, let's subtract 3x from both sides so that we can isolate x:
4x=3x+3
-3x -3x
x=3
<u>So, our x=3, which means that KL=3.</u>
I hope this was helpful, keep learning! :D
Answer:
A and D
Step-by-step explanation:
4×3=12
4×d=4d
12+4d
Then;(4×d)+(3×4)=4d +12
Same expression
Ed because 2 and 8 are equal