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Question 3 of 10 A Assume EFG = JKL. If mLJ = 90°, mL K = 26°, and m< L = 64°, what is the measure of < E?

kumpel [21]

The measure of angle E will be 90 degrees as well.

Assume EFG = JKL.

If mLJ = 90°, mL K = 26°, and m< L = 64°,

<h3>What is the congruent triangle?</h3>

Two triangles are said to be congruent if the length of the sides is equal, a measure of the angles are equal and they can be superimposed.

We have been given an image of two congruent triangles.

Since, EFG = JKL

therefore, the corresponding angles will be congruent.

m < J = 90° = m< E = 90

By congruence measure of angle, J will be equal to the measure of angle E.

Hence, The measure of angle E will be 90 degrees as well.

Learn more about congruent;

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4 0

2 years ago

Solve for the angle x.

sergejj [24]

Answer:

x=45

Step-by-step explanation:

An entire triangle is 180 degrees and you already know that one angle is 90 degrees. 180 - 90 is 90. Now you have the equation 2x=90.

You then divide each side by 2 to get the x by itself which leaves you with x=45.

8 0

2 years ago

Read 2 more answers

Select the expression that has a value of 6.2,400 ÷ 402,400 ÷ 4240 ÷ 40240 ÷ 4

Svetlanka [38]

Answer:

the value is 2.2721803393 x 1400

8 0

2 years ago

M+12=10 what is the answer to this equation?

Fofino [41]

M = -2 is da answer to da equation

8 0

3 years ago

Read 2 more answers

Which is the simplified form of the expression

Elina [12.6K]

Answer:

$\displaystyle A=\frac{ 4 }{ x^{14} y^{8}}$

Step-by-step explanation:

<u>Properties of Powers</u>

The algebraic expression called power has the form x^y where x is called the base and y is called the exponent.

Powers have some properties, some of which we'll recall below

$(x^a)^b=x^{ab}$

$(x^a)(x^b)=x^{a+b}$

$\displaystyle \frac{x^a}{x^b}=x^{a-b}$

$\displaystyle x^{-a}=\frac{1}{x^a}$

$\displaystyle x^{a}=\frac{1}{x^{-a}}$

We'll use those properties to simplify the expression

$\displaystyle A=\left( \frac{ (2)^{-3}(x^{-3}) (y^2) }{(4^{-2}) (x^4) (y^6)} \right)^2$

Taking the power 2 of every term

$\displaystyle A=\frac{ (2)^{-6}(x^{-6}) (y^4) }{(4^{-4}) (x^8) (y^{12})}$

Moving the terms with negative exponent to its opposite side

$\displaystyle A=\frac{ (2)^{-6} (4^{4})(y^4) }{ (x^8)(x^{6}) (y^{12})}$

Operating the explicit same bases

$\displaystyle A=\frac{ (2)^{-6} (4^{4}) }{ (x^{14}) (y^{12-4})}$

Since $4^4=(2^2)^4=2^8$

$\displaystyle A=\frac{ (2)^{-6} (2^8) }{ (x^{14}) (y^{12-4})}$

Operating the remaining like bases subtractions

$\displaystyle A=\frac{ (2^2) }{ (x^{14}) (y^{8})}$

Finally

$\displaystyle A=\frac{ 4 }{ x^{14} y^{8}}$

5 0

3 years ago