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antoniya [11.8K]
3 years ago
8

Quick! worth 20 points use the net to determine the lateral surface area

Mathematics
2 answers:
madam [21]3 years ago
8 0
Ihhhhhhjhjjjhbyy t t
VashaNatasha [74]3 years ago
5 0

Answer:

i think it is 60 cm2

Step-by-step explanation:

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In △ABC, m∠A=44°, m∠B=48°, and a=25. Find c to the nearest tenth.
Nookie1986 [14]

Answer:

=36.0

Step-by-step explanation:

We use the sine rule to find the missing sides as follows;

Lets find the missing angle C by using the summation of interior angles in a triangle.

C=180-(44+48)

=88°

Then,

a/Sin A=c/Sin C

25/Sin 44=c/Sin 88

c=(25 Sin 88)/Sin 44

c=35.97

The side c=36.0 to the nearest tenth.

8 0
3 years ago
Evaluate the indefinite integral.
Oksana_A [137]

Answer:

\frac{1}{3} x^3 - x^2 + 4x

Step-by-step explanation:

All this takes is the use of the power rule, which, for integrals, says that

∫x^n = \frac{1}{n+1}x^{n+1}.

With this in mind, we can integrate:

∫x^2 - 2x + 4

= \frac{1}{3} x^3 - x^2 + 4x.

We can also check our answer by differentiating our answer:

\frac{d}{dx} (\frac{1}{3}x^3 - x^2 + 4x)\\\\ = x^2 - 2x + 4

so we are correct!

hope this helped!

4 0
2 years ago
Find the product of 503×6
Mashutka [201]
3018

Mentally,
503 = 500 + 3
500 times 6 = 3000
3 times 6 = 18
Add them up:
3018
8 0
3 years ago
The length of a rectangular garden is 8 feet longer than it’s width. The garden is surrounded by a sidewalk that is 4 feet wide
Westkost [7]
Answer:

The length = 20
The width = 12 

Explanation:

Let the Length of the garden be L and the Width W 
Therefore the area of the garden = L*W 
But we know that L = W + 8 
Therefore the area of the garden can be expressed as W*(W + 8) 
When the brackets are expanded this equals W^2 + 8W

The area of the recctangle which includes the path and garden will have a length of L + 8 (ie the length of the garden + 4 feet at the top and 4 feet at the bottom) 
The width will be W + 8 (width of garden + 4 feet at the left and 4 feet at the right) 
Therefore the area will be (W + 8)*(L +8) 
Once again we know that L = W + 8 
Therefore the area of the path/garden = (W +8)(W +8 +8) 
=(W +8)(W +16) 
=W^2 +24W + 128 

We know that the path alone has an area of 320 square feet. Therefore if we subtract the area of the garden (W^2 + 8W) from the area of the path/garden the area left is the area of the path only 

Therefore W^2 + 24W + 128 - (W^2 + 8W) = 320 
W^2 + 24W + 128 - W^2 - 8W = 320 
Simplify 
16W + 128 = 320 
Subtract 128 from both sides of the equation 
16W = 192 
divide both sides of the equation by 16 
W = 12 
As L = W + 8 
L = 12 + 8 = 20 
7 0
3 years ago
One student did an experiment with sand, gravel, food coloring and water. the steps of the experiment are shown below. fill abou
Anna35 [415]
The set up of the experiment shows that the student is demonstrating the movement of pollutants through the ground water.
3 0
4 years ago
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