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lesya692 [45]
2 years ago
7

In △ABC, m∠A=44°, m∠B=48°, and a=25. Find c to the nearest tenth.

Mathematics
1 answer:
Nookie1986 [14]2 years ago
8 0

Answer:

=36.0

Step-by-step explanation:

We use the sine rule to find the missing sides as follows;

Lets find the missing angle C by using the summation of interior angles in a triangle.

C=180-(44+48)

=88°

Then,

a/Sin A=c/Sin C

25/Sin 44=c/Sin 88

c=(25 Sin 88)/Sin 44

c=35.97

The side c=36.0 to the nearest tenth.

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In right △ABC with right angle B, m∠A=(3x−8)° and m∠C=(x−2)°.
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Answer:

<A = 67

Step-by-step explanation:

The three angles of a triangle add up to 180 degrees.  We know a right angle is 90 degrees.

<A + <B + <C = 180

3x-8 + 90 + x-2 =180

Combine like terms

4x-10+90 = 180

4x+80 =180

Subtract 80 from each side

4x+80-80=180-80

4x=100

Divide each side by 4

4x/4 = 100/4

x=25

But we want to know <A

<A = 3x-8

 Substitute x=25

    =3(25) -8

    =75-8

   = 67


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