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andrey2020 [161]
3 years ago
14

Order from least to greatest

Mathematics
1 answer:
ddd [48]3 years ago
7 0
Your answer will be :

the square root of 14, the square root of 54/3, 6.8, the square root of 26/3.
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Simplify 4x + 3(5x) + 4y - x =​
nataly862011 [7]

Answer:

= 18x + 4y hope this helps :)

Step-by-step explanation:

8 0
2 years ago
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Please help i am super confused on what to do :)
Ludmilka [50]

Answer:

About 9.1 yards tall.

Step-by-step explanation:

So, we can draw the right triangle shown below:

We want to find h.

Since we know the angle and the side adjacent to the angle and we wan to find the opposite side, we will use the tangent ratio:

\displaystyle \tan(x^\circ)=\frac{\text{Opposite}}{\text{Adjacent}}

So:

\displaystyle \tan(20)=\frac{h}{25}

Therefore:

\displaystyle h=25\tan(20)

Use a calculator. Ensure your calculator is in the correct mode (degrees mode):

h\approx 9.1\text{ yards}

The goal post is around 9.1 yards tall.

7 0
3 years ago
Graph the Systems of Equations below, then place a point indicating the solution to the system of equations.
dimulka [17.4K]

Answer:

Solution in image belo, make sure to put the lines on the right number's then out the point on (4, -3)

5 0
3 years ago
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A bucket that weighs 6 lb and a rope of negligible weight are used to draw water from a well that is 80 ft deep. The bucket is f
zaharov [31]

Answer:

3200 ft-lb

Step-by-step explanation:

To answer this question, we need to find the force applied by the rope on the bucket at time t

At t=0, the weight of the bucket is 6+36=42 \mathrm{lb}

After t seconds, the weight of the bucket is 42-0.15 t \mathrm{lb}

Since the acceleration of the bucket is the force on the bucket by the rope is equal to the weight of the bucket.

If the upward direction is positive, the displacement after t seconds is x=1.5 t

Since the well is 80 ft deep, the time to pull out the bucket is \frac{80}{2}=40 \mathrm{~s}

We are now ready to calculate the work done by the rope on the bucket.

Since the displacement and the force are in the same direction, we can write

W=\int_{t=0}^{t=36} F d x

Use x=1.5 t and F=42-0.15 t

W=\int_{0}^{36}(42-0.15 t)(1.5 d t)

=\int_{0}^{36} 63-0.225 t d t

=63 \cdot 36-0.2 \cdot 36^{2}-0=3200 \mathrm{ft} \cdot \mathrm{lb}

=\left[63 t-0.2 t^{2}\right]_{0}^{36}

W=3200 \mathrm{ft} \cdot \mathrm{lb}

4 0
3 years ago
Dexter was asked to mix the punch for his sister’s birthday party. He has to figure out how much water and pure concentrate to a
Zigmanuir [339]

Answer:

  6 liters

Step-by-step explanation:

Let x represent the amount of pure concentrate used to make the punch. Then the total amount of concentrate in the punch is ...

 0.20·10 +1.00x = 0.50(10+x)

  x +2 = 0.5x +5 . . . . . eliminate parentheses

  0.5x = 3 . . . . . . . . . . .subtract 2+0.5x

  x = 6 . . . . . . . . . . . . . multiply by 2

6 liters of pure concentrate must be added to make a 50% punch.

5 0
3 years ago
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