Answer:
the soil was dry so i watered your plant
To make Paramecium Contractile vacuole concentration graph useful the salt concentrations descriptions should replaced with actual values.
Thus, option "A" is correct.
What is Paramecium Contractile vacuole
"It is a sub-cellular structure (organelle) involved in osmoregulation."
<h3>What is a graph?</h3>
"A diagram (such as a series of one or more points, lines, line segments, curves, or areas) that represents the variation of a variable in comparison with that of one or more other variables."
<h3>What does the graph in the given question depict?</h3>
It shows that the Paramecium Contractile Vacuole concentration per minute decreases as salt concentration increases.
But the concentration of salt is not mention in quantity so its not clear what are the lowest and highest concentration affecting Paramecium Contractile Vacuole.
Hence, the Paramecium Contractile Vacuole concentration graph can be more useful if the actual values of salt concentration will be mentioned.
To know more about Paramecium Contractile Vacuole here
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Answer:
Angular speed of the bacteria motor is 1447rad/s
t = 4.342 × 10^-3 seconds
Explanation:
Hint: Do you remember circular motion in physics???
Okay, let's go
Given:
radius of 1.61 10-8 m
tangential speed at the rim of 2.33 10-5 m/s
Let's recall that angular velocity
ω = Vt/r
Where,
Vt = 2.33 10-5 m/s
r = 1.61 10-8 m
ω = ?
ω = 2.33 ×10-5 m/s = 1447rad/s
1.61 ×10-8 m
Angular speed of the bacteria motor is 1447rad/s
Let's find the elapsed time too
Since The angular velocity is said to be constant, there will be no acceleration (a = 0)
Using:
θ = ωot + (1/2at^2)
t = θ/ωo
(θ = 1 revolution or 2π rad, ωo = 1447rad/s)
t = (2π rad)/(1447 rad/s)
t = 4.342 × 10^-3 seconds
Answer:
<u>Part A</u> : 70 secondary oocytes will be formed.
<u>Part B</u> : 70 first polar bodies will be formed.
<u>Part C</u> : 70 ootids will be formed.
Explanation:
During oogenesis growth maturation of a single oogonium produces one primary oogonium.
the primary oogonium then undergoes meiosis -1 and produces one secondary oocyte and first polar body.
The secondary oocyte then undergoes meiosis - 2 and forms an ootid and second polar body.
The ootid then differentiates into the ovum.
As in the above scenario , 70 primary oocytes are present , they undergo meiosis-1 and produces 70 secondary oocytes and 70 first polar bodies. Hence answers of part A and B is 70.
As 70 secondary oocytes are formed , they undergo meiosis -2 and forms 70 ootids which then differentiate in 70 ovums.
Answer: Decrease the amount of animal waste that reaches the water supply.
A fecal coliform is an anaerobic, rod shaped and gram-negative bacteria. It originates in the intestines of warm blooded organisms. It is released in the fecal matter of humans and animals. This bacterial strain is a chief contaminant of water body. The waterborne diseases associated in humans because of this bacterial strain includes infection of ears, bacterial and viral gastroenteritis, typhoid fever and hepatitis A. The bacterial strain is added to water body by discharge of human sewage, pet animal feces runoff and agricultural wastes including animal fecal based manure runoff.
Therefore, by decreasing the amount of animal waste that reaches the water supply is an appropriate action that Florida farm could take to reduce fecal caliform in nearby water supplies.
