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erastova [34]
3 years ago
8

Will mark brainliest if I can.

Mathematics
1 answer:
OLEGan [10]3 years ago
5 0

Answer:

(0, -4)

(2,0)

Step-by-step explanation:

Basically x intercept is (0, -4)

Y intercept is (2, 0)

Hope I helped!

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I need this answered asap please and thankyou :D
suter [353]

Answer:

b

Step-by-step explanation:

5 0
3 years ago
Two points on the line are (0, 4) and (7, 18). Use the points to first determine the slope and y-intercept. Then write the equat
Nadya [2.5K]

9514 1404 393

Answer:

  a.  m = 2; y intercept = (0, 4); y = 2 x + 4

Step-by-step explanation:

The slope can be found using the formula ...

  m = (y2 -y1)/(x2 -x1)

  m = (18 -4)/(7 -0) = 14/7

  m = 2

The y-intercept is the first given point: (0, 4).

The equation for the line in slope-intercept form is

  y = mx + b

Here, we have m=2 and b=4, so the equation is ...

  y = 2x +4

6 0
2 years ago
What is the range of f(x)=(3/4)^x - 4 a.{y|y > -4} b.{y|y>3/4} c.{y|y<- 4} d.{y|y/4}
Vanyuwa [196]
3/4 *x-4
3/4 x 3/4 x 3/4 x 3/4
3 13/81

8 0
3 years ago
A ferry will safely accommodate 82 tons of passenger cars. Assume that the meanweight of a passenger car is 2 tons with standard
Shalnov [3]

Answer:

The probability that the maximum safe-weight will be exceeded is <u>0.0455 or 4.55%</u>.

Step-by-step explanation:

Given:

Maximum safe-weight of 37 cars = 82 tons

∴ Maximum safe-weight of 1 car (x) = 82 ÷ 37 = 2.22 tons (Unitary method)

Mean weight of 1 car (μ) = 2 tons

Standard deviation of 37 cars = 0.8 tons

So, standard deviation of 1 car is given as:

\sigma=\frac{0.8}{\sqrt{37}}=0.13

Probability that maximum safe-weight is exceeded, P(x > 2.22) = ?

The sample is normally distributed (Assume)

Now, let us determine the z-score of the mean weight.

The z-score is given as:

z=\frac{x-\mu}{\sigma}\\\\z=\frac{2.22-2}{0.13}\\\\z=\frac{0.22}{0.13}=1.69

Now, finding P(x > 2.22) is same as finding P(z > 1.69).

From the z-score table of normal distribution curve, the value of area under the curve for z < 1.69 is 0.9545.

But we need the area under the curve for z > 1.69.

So, we subtract from the total area. Total area is 1 or 100%.

So, P(z > 1.69) = 1 - P(z < 1.69)

P(z>1.69)=1-0.9545=0.0455\ or\ 4.55\%

Therefore, the probability that the maximum safe-weight will be exceeded is 0.0455 or 4.55%.

8 0
3 years ago
I will mark either the best or the first answer brainliest.
posledela

Answer:

11.x=16 12.x=37

Step-by-step explanation:

11.

20^2-12^2=x^2

256=x^2

x=√256

x=16

12.

13^2-5^2=y^2

144=y^2

y=12

/

y^2+35^2=x^2

12^2+35^2=x^2

1369=x^2

x=37

5 0
3 years ago
Read 2 more answers
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