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2 years ago

As an estimation we are told £3 is €4. Convert £6 to euros.

Mathematics

1 answer:

suter [353]2 years ago

5 0

Answer:

This would just simply be doubling €4.

So,

If £3 is doubled to £6

Then €4 is doubled to €8

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I put a picture<br><br> —PLEASE HELP

Karo-lina-s [1.5K]

$▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪$

Base of a cube is a square, and in the given figure it's stated that the measure of each side is " x " ft

Therefore it's Area is equal to : -

$side \times side$

$x \times x$

${x}^{2}$

Now, since it's Area is given as 1/4 ft², let's equate the Areas to find the measure of each side ~

that is ~

${x}^{2} = \dfrac{1}{4}$

$x = \sqrt{ \dfrac{1}{2} \times \dfrac{1}{2} }$

$x = \dfrac{1}{2} \: \: feet$

It's time to find the volume of cube that is ~

$(side) {}^{3}$

So, let's plug the value of side length (1/2 ft)

Volume is equal to ~

${ \bigg(\dfrac{1}{2} \bigg) }^{3}$

$\dfrac{1}{8} \: \: ft {}^{3}$

Hence, the required 1/8 or 0.125 ft³

I hope it helped ~

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2 years ago

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Mei is trying to list as many prime numbers as she can for a challenge problem for her math class. She finds

Svet_ta [14]

Hello,

Since the degree of a polynomial is the highest exponent present, the degree of Mei’s polynomial should be 2.

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2 years ago

$12,800 at 12% for 3 years find the total amount ?

HACTEHA [7]

Answer:

so first you do

12800*.12 which is 1536

so $1536 for 1 year

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1536*3=

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3 years ago

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2 years ago

Assuming that the sample mean carapace length is greater than 3.39 inches, what is the probability that the sample mean carapace

joja [24]

Answer:

The answer is "".

Step-by-step explanation:

Please find the complete question in the attached file.

We select a sample size n from the confidence interval with the mean $\mu$ and default $\sigma$ , then the mean take seriously given as the straight line with a z score given by the confidence interval

$\mu=3.87\\\\\sigma=2.01\\\\n=110\\\\$

Using formula:

$z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}$

The probability that perhaps the mean shells length of the sample is over 4.03 pounds is

$P(X>4.03)=P(z>\frac{4.03-3.87}{\frac{2.01}{\sqrt{110}}})=P(z>0.8349)$

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$=\textup{NORM.S.DIST(0.8349,TRUE)}\\\\P(z$

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2 years ago