Answer:The base of the ladder from the tree is 28ft
Step-by-step explanation:
Using pythagorean theorem
Let 100ft= hypothesis is the right angle triangle
Let 96ft be the height of the ladder
Let x be the base of the right angle triangle between the base of the ladder and the tree
h^2=a^2+b^2
100^2=96^2 +b^2
10,000=9216 +b^2
b^2=10,000-9216
b=sqrt(784)
b=28ft
Answer:
I think it might be $123.75
<span>the particle's initial position is at t=0, x = 0 - 0 + 4 = 4m
velocity is rate of change of displacement = dx/dt = d(t^3 - 9t^2 +4)/dt
= 3t^2 - 18t
acceleration is rate of change of velocity = d(3t^2 -18t)/dt
= 6t - 18
</span><span>the particle is stationary when velocity = 0, so 3t^2 - 18t =0
</span>3t*(t - 6) = 0
t = 0 or t = 6s
acceleration = 6t - 18 = 0
t = 3s
at t = 3s, velocity = 3(3^2) -18*3 = -27m/s
displacement = 3^3 - 9*3^2 +4 = -50m
