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marissa [1.9K]
3 years ago
13

What are two of the benefits of earning college credit in high school?

Advanced Placement (AP)
2 answers:
lesya692 [45]3 years ago
6 0

Answer:

B.paying less for tuition

Explanation:

This is the answer because high school credits are known for always cutting down on tuition and also making it easer to get into a good college if wanted.

Please MARK BRAINLEST.

Alexxandr [17]3 years ago
5 0

Answer:  (Paying less for tuition) AND (Graduating college early)

Explanation:

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\bold{\huge{\pink{\underline{ Solution }}}}

<h3><u>Given </u><u>:</u><u>-</u></h3>

  • <u>We </u><u>have </u><u>given </u><u>one </u><u>irregular </u><u>figure </u><u>which </u><u>is </u><u>composed </u><u>2</u><u> </u><u>triangle's </u><u>and </u><u>3</u><u> </u><u>rectangles </u>
  • <u>The </u><u>height </u><u>and </u><u>base </u><u>of </u><u>the </u><u>triangles</u><u> </u><u>is </u><u>6cm </u><u>and </u><u>7</u><u> </u><u>cm</u><u> </u><u>each </u>
  • <u>The </u><u>length </u><u>and </u><u>breath </u><u>of </u><u>the </u><u>rectangles</u><u> </u><u>is </u><u>1</u><u>3</u><u>.</u><u>1</u><u> </u><u>cm </u><u>and </u><u>7cm </u><u>each </u>

<h3><u>To </u><u>Find </u><u>:</u><u>-</u></h3>

  • <u>We </u><u>have </u><u>to </u><u>find </u><u>the </u><u>total </u><u>surface </u><u>area </u><u>of </u><u>the </u><u>given </u><u>figure</u><u>? </u>

<h3><u>Let's </u><u>Begin </u><u>:</u><u>-</u></h3>

<u>We </u><u>have</u><u>, </u>

  • 2 triangles of height 6 cm and base 7cm each
  • 3 rectangles of length 13.1 cm and 7cm each

<u>Therefore</u><u> </u><u>,</u>

<u>We </u><u>know </u><u>that</u><u>, </u>

Area of triangle

\bold{=}{\bold{\pink{\dfrac{1}{2}}}}{\bold{\pink{ × Base × Height }}}

<u>Subsitute </u><u>the </u><u>required </u><u>values</u><u>, </u>

<u>Area </u><u>of </u><u>1</u><u> </u><u>triangle </u>

\sf{=}{\sf{\dfrac{1}{2}}}{\sf{ × 7 × 6 }}

\sf{ = 7 × 3 }

\sf{ = 21 cm²}

<h3><u>Therefore</u><u>, </u></h3>

<u>Area </u><u>of </u><u>2</u><u> </u><u>triangle's </u>

\sf{ = 2 × ( Area\:of\:1\:traingle) }

\sf{ = 2 × 21 }

\sf{ = 42 cm² }

Thus, The area of 2 triangles is 42 cm²

<h3><u>Now</u><u>, </u></h3>

<u>We </u><u>know </u><u>that</u><u>, </u>

Area of rectangle

\bold{\red{ = Length × Breath }}

<u>Subsitute </u><u>the </u><u>required </u><u>values</u><u>, </u>

Area of 1 rectangle

\sf{ = 13.1 × 7 }

\sf{ = 91.7 cm² }

<h3><u>Therefore</u><u>,</u></h3>

<u>Area </u><u>of </u><u>3</u><u> </u><u>rectangles </u>

\sf{ = 3 ×( Area\:of\:1\:rectangle)  }

\sf{ = 3 × 91.7 }

\sf{ = 275.1 cm² }

Thus, The area of 3 rectangle is 275.1 cm²

<h3><u>So</u><u>, </u></h3>

Total area of the given figure

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\sf{ = 42 + 275.1 }

\bold{ = 317.1 cm²}

Hence, The total surface area of the given figure is 317.1 cm² .

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