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Arisa [49]
3 years ago
14

The one-to-one functions g and h are defined as follows. HELP PLEASE

Mathematics
1 answer:
vazorg [7]3 years ago
3 0

Answer:

2, (x+13)/6, -7

Step-by-step explanation:

The -1 bit means do it backwards, so look the for the output of the function with the value given.

In g, when we put in 2 we get 9 out, so g^-1(9) is 2.

For the second one we need to rearrange it to get x = something.

h(x) + 13 = 6x

x = (h(x) + 13)/6

Then replace the h(x) with x and the x with h^-1(x) to get

h^-1(x) = (x + 13)/6

The last one is a trick. Note that h and h^-1 are opposites. If we do something then do the opposite of it, we haven't done anything at all! So the number stays the same.

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Answer:

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Answer:

36(5)^-2.

Step-by-step explanation:

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7 0
3 years ago
How do you solve y=x-3 and<br> Y= -x +5
artcher [175]

Answer:

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4 years ago
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