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3 years ago

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Mathematics

2 answers:

zavuch27 [327]3 years ago

7 0

Answer:

$\frac{5}{x} = - 6 \\ \\ - 6x = 5 \\ \\ x = - \frac{5}{ 6} = - 0.83$

I hope I helped you^_^

Mashcka [7]3 years ago

6 0

Answer:

I am confused what is the question?

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( I WILL BE GIVING EXTRA POINTS AND BRAINLIEST TO WHO EVER HELPS ME!! :D)

KatRina [158]

Answer:

B I think

Step-by-step explanation:

Eight eighths in one cup. Took that and multiplied that and added the single eighth. Six sixths in one cup. Took that and multiplied that and added the single sixth again. Added the total up and got 10.2916666667. Rounded. Hope this helps!

3 0

3 years ago

Read 2 more answers

4cm 8cm 5 cm 15cm 9cm ?cm find the missing side length

Vlad [161]

Is/Was there a shape that goes with this?

4 0

3 years ago

SOLVE THIS PROBLEM ASAP PLS

deff fn [24]

Answer:

See attached

Step-by-step explanation:

-> Also see attached

Have a nice day!

I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)

- Heather

7 0

3 years ago

What is the coefficient in the algebraic expression 7 xy2 ?

Monica [59]

The answer is 7!

The number In front of the variable is always the coefficient.

5 0

3 years ago

Explain why f(x) = x^2+4x+3/x^2-x-2 is not continuous at x = -1.

liberstina [14]

Answer:

The value of x = -1 makes the denominator of the function equal to zero. That is why this value is not included in the domain of f(x)

Step-by-step explanation:

We have the following expression

$f(x) = \frac{x^2+4x+3}{x^2-x-2}$

Since the division between zero is not defined then the function f(x) can not include the values of x that make the denominator of the function zero.

Now we search that values of x make 0 the denominator factoring the polynomial $x^2-x-2$

We need two numbers that when adding them get as a result -1 and when multiplying those numbers, obtain -2 as a result.

These numbers are -2 and 1

Then the factors are:

$(x-2) (x + 1)$

We do the same with the numerator

$x^2+4x+3$

We need two numbers that when adding them get as a result 4 and when multiplying those numbers, obtain 3 as a result.

These numbers are 3 and 1

Then the factors are:

$(x+3)(x + 1)$

Therefore

$f(x) = \frac{(x+3)(x+1)}{(x-2)(x+1)}$

Note that $\frac{(x+1)}{(x+1)}=1$ only if $x \neq -1$

So since $x = -1$ is not included in the domain the function has a discontinuity in $x = -1$

3 0

3 years ago