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Alexandra [31]
3 years ago
7

HELP!!! ASAP!!! THANK YOU !! 10 POINTS <333

Mathematics
1 answer:
olchik [2.2K]3 years ago
4 0

Answer:

your answer would be c (7)

Step-by-step explanation:

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19 is less than 48 by what percentage?
vampirchik [111]
<span>19 is less than 48 by what percentage:
Let;s find out how many percent is the difference.
=> 48 - 19 = 29.
Next is to solve for the percentage
=> 29 / 48 = </span>0.60,
=> 0.60 * 100% = 60%
Thus, 19 is 60% lesser than 48.
4 0
3 years ago
25 is what over less or = to 384 oz
babunello [35]

Answer:

There are sixteen ounces in a pound, so 25 pounds (lbs) is 400 ounces (oz). 400>384. So, 25 lbs is bigger than 384 oz

Step-by-step explanation:

7 0
3 years ago
Let A be a 3 by 6 , B be a 6 by 7 and C be a 7 by 3 matrix. Determine the size of the following matrices (if they do not exist,
kozerog [31]

Answer:

a. AB: 3 by 7

b. BA: N by N

c. A^TB: N by N

d. BC: 6 by 3

Step-by-step explanation:

Given

A =3\ by\ 6

B =6\ by\ 7

C =7\ by\ 3

Required

The dimension of the following matrices

As a general rule:

For A * B to be successful, the columns in a must equal the rows in B

Using this rule, we have:

A_{m*n} * B_{n * p} = AB_{m*p}

So:

(a)\ AB

A_{3*6} * B_{6*7} \to AB_{3 * 7}

(b)\ BA

B_{6*7} * A_{3*6} \to AB_{N * N}

The column numbers of B does not equal the row numbers of A.

Hence, BA does not exist

(c)\ A^TB

A^T implies that:

If A =3\ by\ 6, then

A^T = 6\ by\ 3

So:

A^T_{6*3} * B_{6,7} \to A^TB_{N*N}

The column numbers of A^T does not equal the row numbers of B.

Hence, A^TB does not exist

(d)\ BC

B_{6*7} * C_{7*3} \to BC_{6,3}

6 0
3 years ago
give the most general solutions to equations. . 2sinxcosx-sin(2x)cos(2x)=0. . A. simplify the first expression using double angl
Zinaida [17]
2sinxcosx - sin(2x)cos(2x) = 0 

<span>Part I </span>
<span>The double angle identity for sine states that sin(2x) = 2sinxcosx </span>
<span>Thus we get: </span>
<span>sin(2x) - sin(2x)cos(2x) = 0 </span>

<span>Part II </span>
<span>sin(2x)(1 - cos(2x)) = 0 </span>

<span>Part III </span>
<span>Either sin(2x) = 0 or </span>
<span>1 - cos(2x) = 0 </span>
<span>=> cos(2x) = 1 </span>

<span>For sin(2x) = 0, this is true for </span>
<span>2x = n(pi) where n = 0, 1, 2, .... </span>
<span>x = n(pi/2) </span>

<span>For cos(2x) = 1, this is true for </span>
<span>2x = n(pi) where n = 0, 2, 4, .... </span>
<span>x = n(pi/2)
</span>

I hope my answer has come to your help. Thank you for posting your question here in Brainly.
5 0
3 years ago
Find the midpoint of the segment with the given endpoints. ​ (9​,9​) and ​(6​,8​)
mars1129 [50]

<u>Answer:</u>

The mid-point is (7.5, 8.5).

<u>Step-by-step explanation:</u>

We are given two points (9​,9​) and ​(6​,8​) as the endpoints for a line segment and we are to find the midpoint of this segment.

We know that the formula for finding the mid point is:

<em>Mid point = (\frac {x_1 + x_1 }{ 2 } ,\frac { y_1 + y_2} {2} )</em>

So substituting the given values of the coordinates of the endpoints in the above formula to get:

= (\frac {9 + 6}{2} , \frac {9 + 8}{2} )

= (\frac {15}{2} , \frac {17} {2} )

=(7.5, 8.5)

Therefore, the mid-point is (7.5, 8.5).

4 0
3 years ago
Read 2 more answers
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