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aleksley [76]
2 years ago
10

PLEASE HURRY!!!! Find the slope of the line.

Mathematics
2 answers:
Blababa [14]2 years ago
5 0

Answer:

B!

Step-by-step explanation:

Fantom [35]2 years ago
5 0

Answer:

D

Step-by-step explanation:

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How do you eliminate the parameter theta to find a Cartesian equation of the curve: x=sin(1/2 theta), y=cos(1/2 theta), 0 is les
kiruha [24]
The answer to the problem is as follows:

x = sin(t/2) 
<span>y = cos(t/2) </span>

<span>Square both equations and add to eliminate the parameter t: </span>

<span>x^2 + y^2 = sin^2(t/2) + cos^2(t/2) = 1 </span>

<span>The final step is translating the original parameter limits into limits on x and y. Over the -Pi to +Pi range of t, x varies from -1 to +1, whereas y varies from 0 to 1. Thus we have the semicircle in quadrants I and II: y >= 0.</span>
6 0
3 years ago
Solve the following system of equations algebraically:<br> Y = x^2 + 8x – 9<br> Y = 2x + 7
julia-pushkina [17]
Use simultaneous equations:
2x + 7 = x^2 + 8x - 9
7 = x^2 + 6x - 9
16 = x^2 + 6x
+ or - 4 = 7x
answer is
-4/7 or 4/7
3 0
2 years ago
I NEED HELP WITH THESE TWO QUESTIONS PLZ DO NOT ANSWER IF YOU CANNOT EXPLAIN THE ANSWER
Murljashka [212]

9514 1404 393

Answer:

  1. asymptotes: x=-6, x=6, y=0; zero: x=0

  2. 20 blue fish

Step-by-step explanation:

1. The vertical asymptotes are where the denominator is zero. It factors as (x-6)(x+6), so will have zeros at x=-6 and x=6.

The horizontal asymptote is at the limit when x goes to infinity. Here, the ratio of highest-degree terms is 6/x, so the value goes to zero as x gets large.

The zero is where the numerator is zero, at x=0.

In summary:

  • vertical asymptotes: x = ±6
  • horizontal asymptote: y = 0
  • zero: (0, 0)

__

2. 60% are red, so 40% are blue. The difference in percentages is 60%-40% = 20%. The percentage of blue fish (40%) is twice the difference (=2×20%), so the number of blue fish is twice the difference in numbers.

  blue fish = 2×10 = 20 fish

<em><u>Check</u></em>

There are then 20+10=30 red fish, so 20+30=50 fish total. Reds are 30/50 = 60% of the total.

<u><em>Additional comment</em></u>

I find it often works well to work with ratios, which I can often do in my head. Other folks like to see equations. Here, we could write equations like ...

  r = 60%(r + b) . . . . reds are 60% of the total

  r - b = 10 . . . . . . . . 10 more reds than blues

We want the value of b, so we can eliminate r by substituting for it:

  r = 10 + b . . . . from the second equation above

  (10 +b) = 0.60((10 +b) + b) . . . . substitute for r

  10 +b = 6 + 1.2b . . . simplify

  4 = 0.2b . . . . subtract b+6

  20 = b . . . . . . multiply by 5 (there are 20 blue fish)

6 0
3 years ago
Two equation Ax+By=1 and (3,-1)(-2,-2). Find A and B​
sdas [7]

IT IS Biodarmate physical access process in great Aphrodite in which is will be used when both the variable size will be multiplied with both

4 0
3 years ago
Find the measures of EAF DAE and CAD
sdas [7]
You have to build an equation to find the answer,

angles in a straight line add upto 180° 
so your equation would be,

12x+30°=180°
      -30    -30
=12x=150°
   ÷12  ÷12
=x=12.5°

now find the measures of the angles by using 12.5 as x.

angle EAF= 2x
                 =2×12.5
                 =25° degrees

angle DAE= 4x
                 =4×12.5
                 =50°degrees

angle CAD=6x
                 =6×12.5
                 =75°degrees

check,
30+25+50+75=180°degrees

hope this helps.......
7 0
3 years ago
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