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3 years ago

What is the domain of the function of y=√x+8 -7

Mathematics

1 answer:

kirza4 [7]3 years ago

8 0

Answer:

Step-by-step explanation:

Recall that the argument of the square root function y = √x must always be 0 or greater.

If you meant y=√x+8 -7, the domain is therefore [0, infinity).

But if you meant y=√(x+8) -7, the domain is [-8, infinity).

Those parentheses are important!

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Find the missing part.

Katarina [22]

Answer:

$z = 15[\frac{\sqrt{3}}{2}]$

Step-by-step explanation:

To find the Z-side, we must take the cosine of the 30-degree angle of the main triangle

We know that the cosine of an angle is defined as:

$cos(30) = \frac{adjacent\ side}{hypotenuse}$

$cos(30) = \frac{\sqrt{3}}{2}$

$\frac{\sqrt{3}}{2}} = \frac{z}{15}$

Then:

$z = 15[\frac{\sqrt{3}}{2}}]$

Finalmente the side z is:

$z = 15[\frac{\sqrt{3}}{2}}]$

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Answer:

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Step-by-step explanation:

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alexira [117]

Answer:

The graph is shown below.

Step-by-step explanation:

Given:

The relationship between the variables 'x' and 'y' is proportional relationship.

A proportional relationship is of the form:

$y=mx$

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Now, it is given that 'y' is one-half of the value of 'x'. Framing it in equation form, we get:

$y=\frac{1}{2}x$

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So, in order to get slope equal to one-half, we need to move 2 units along the x-axis from the origin and then 1 unit parallel to y-axis to get to the next point. The point is (2, 1).

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