You want to end up with
. Expand this using the angle sum identity for sine:

We want this to line up with
. Right away, we know
.
We also need to have

Recall that
for all
; this means

Then

So we end up with

A, C, D are the correct answers.
-5 is neither a whole number nor a natural number. This is because negative numbers are not included in these. Hope this helps! Let me know:)
(b^4)^3
To simplify when something is raised to two different exponents, multiply the two exponents together:
4 * 3 = 12
You now have b^12.
The answer is D.
Answer:
y = 6x
Step-by-step explanation:
For a vertical stretch, you simply multiply x by the factor you want to stretch it by. 3x • 2 is 6x.
Let the number be n.
Then:
n^2 + (1/n)^2 = 82/9; find n. Find the LCD; it is 9n^2.
Mult all 3 terms by 9n^2:
82*9n^2
9n^4 + 9 = (82/9)(9n^2) => 9n^4 + 9 = ------------
9
Then 9n^4 - 82n^2 + 9 = 0
I used my graphing calculator to find that n = 3.
Let's check: is 3^2 + (1/3)^2 = 82/9?
Is 9 + 1/9 = 82/9?
Is 81 + 1 = 82? YES. So, n=3 is a solution.