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I am Lyosha [343]
4 years ago
14

Are triangles PRU and STQ congruent?

Mathematics
1 answer:
san4es73 [151]4 years ago
7 0

No, triangles PRU and STQ are not congruent. Even though their angles are the same, different triangles can be constructed out of triangles with the same angles. Looking at the picture, one can also see the difference in size between the two triangles.

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HELP ASAP!!!!! If the big triangle below has an area of 20 m squared what does x equal
PSYCHO15rus [73]

Answer:

20 = (x + 1) \times 10 \times 0.5 \\  = 5 \times (x + 1)  \\  x + 1 = 20 \div 5 = 4 \\ x = 4 - 1 = 3 \\ enjoy \: it

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3 years ago
the value of k so that the line Containing the points (-8,k) and (-4,-8) is perpendicular) to the line containing the points (10
In-s [12.5K]

Answer:

k= \frac{-34}{3}

Step-by-step explanation:

<u>Step 1 :</u>-

<u>Perpendicular condition :-</u>

<u>Step 1:-</u>

Two non-vertical lines are perpendicular to each other if and only if their slopes are negative reciprocals of each other.

m_{2} = \frac{-1}{m_{1} }

m_{1} m_{2} = -1

<u>Step 2:-</u>

The given points are (-8,k) and (-4,-8)

m_{1} = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

finding slope of the first line is m_{1}

using formula m_{1} = \frac{-8-k}{-4+8}

=  \frac{-8-k}{4}

finding slope of the second line is m_{2}

using formula m_{2} = \frac{--5+11}{5-10}

=  \frac{6}{-5}

<u>Step 3:</u>-

using perpendicular condition

The two lines are perpendicular and their slopes are

m_{1} m_{2} = -1

(\frac{-k-8}{4} )(\frac{-6}{5} )= -1

simplification,we get solution is

\frac{6(k+8)}{20} =-1

6 k+48 =-20

6 k = -20 -48

6 k = -68

\frac{-68}{6}

k= \frac{-34}{3}

<u>Final answer is </u>

k= \frac{-34}{3}

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1                 1.5

2                  3

3                 4.5

4                 6          

To find any number, create a ratio of 1/1.5=cups of sugar/cups of flour then cross multiply and solve to get any answer you may need.

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Answer:

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D=M/V

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