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blsea [12.9K]
2 years ago
9

Which correctly compares the medians and the measures of variability of the data in the box plots? Select three

Mathematics
2 answers:
LenKa [72]2 years ago
5 0

Answer:

Yes it is right

Step-by-step explanation:

Verizon [17]2 years ago
4 0
Anwser: yes its right


step by step explanation:
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Y=2x-4 -21x + 3y = 3
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It's a stretch, but I'm gonna guess Y = 12.

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Each week, Stephanie is paid a $180 base salary and a 3% commission on her total sales generated for the week. Which expression
prisoha [69]
The expression that represents her weekly income is:
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Approximate the value of the series to within an error of at most 10−510−5. ∑n=1[infinity](−1)n+1n7 ∑n=1[infinity](−1)n+1n7 Acco
alexgriva [62]

Answer:

0.992596

Step-by-step explanation:

3 0
3 years ago
Either enter an exact answer in terms of T or use 3.14 for 7 and enter your answer as a decimal.
muminat

Answer:

N CCX  XN

Step-by-step explanation:

7 0
2 years ago
Please answer correctly !!!!!!!!! Will<br> Mark brainliest !!!!!!!!!!!!!
il63 [147K]

Answer:

x=-\frac{-20+\sqrt{-20w+3600}}{10},\:x=-\frac{-20-\sqrt{-20w+3600}}{10}

Step-by-step explanation:

w=-5\left(x-8\right)\left(x+4\right)\\\mathrm{Expand\:}-5\left(x-8\right)\left(x+4\right):\quad -5x^2+20x+160\\w=-5x^2+20x+160\\Switch\:sides\\-5x^2+20x+160=w\\\mathrm{Subtract\:}w\mathrm{\:from\:both\:sides}\\-5x^2+20x+160-w=w-w\\Simplify\\-5x^2+20x+160-w=0\\Solve\:with\:the\:quadratic\:formula\\\mathrm{Quadratic\:Equation\:Formula:}\\\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

\mathrm{For\:}\quad a=-5,\:b=20,\:c=160-w:\quad x_{1,\:2}=\frac{-20\pm \sqrt{20^2-4\left(-5\right)\left(160-w\right)}}{2\left(-5\right)}\\x=\frac{-20+\sqrt{20^2-4\left(-5\right)\left(160-w\right)}}{2\left(-5\right)}:\quad -\frac{-20+\sqrt{-20w+3600}}{10}\\x=\frac{-20-\sqrt{20^2-4\left(-5\right)\left(160-w\right)}}{2\left(-5\right)}:\quad -\frac{-20-\sqrt{-20w+3600}}{10}\\The\:solutions\:to\:the\:quadratic\:equation\:are\\x=-\frac{-20+\sqrt{-20w+3600}}{10},\:x=-\frac{-20-\sqrt{-20w+3600}}{10}

6 0
3 years ago
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