Given <span>vu=st, sv=tu
</span>STUV is a parallelogram : If both pairs of opp. sides of a quad. are , then the quad is a parallelogram.
VX, XT = The diagonals of a parallelogram bisect each other.
Answer:
Step-by-step explanation:
The applicable rule of exponents is ...
(a^b)(a^c) = a^(b+c)
_____
<em>Comment on the rule of exponents</em>
You can see where the rule comes from when you consider that an exponent signifies repeated multiplication.
x² = x·x . . . . . . the 2 signifies that x is a factor 2 times
x³ = x·x·x . . . . the 3 signifies that x is a factor 3 times
The product of these is ...
(x²)(x³) = (x·x)(x·x·x) = x·x·x·x·x = x⁵ = x²⁺³
Step-by-step explanation:
there is something wrong with your question.
there is no parallelogram with 8 and 6 ft side lengths that has an area of 54 ft².
the maximum area of a parallelogram with 8 and 6 ft side lengths is 48 ft². and that is a rectangle 8×6 as a special form of a parallelogram.
the area of any parallelogram is calculated
Ap = base length × height
and height is the length of the line perpendicular to the base line to one of the corners on the opposite side (as long as the base line).
if Ap = 54, and the base length is 8, this means
54 = 8 × height
height = 54/8 = 6.75 ft
but the height can only be the length of a side connected to the base line or less. not longer.
and in our example here, this connected side is 6. so, the height can only be 6 or less. not 6.75.
so, there must be something wrong with your numbers.
once you get the actual numbers, use my approach above with them (replace whatever number is wrong here by the true value).
3(4) + 12 + 12[4(6) - 10]
12 + 12 + 12(24 - 10)
12 + 12 + 288 - 120
192
A=p(1+i/m)^mn
A=3,500×(1+0.0229÷12)^(12×6)
A=4,014.98
