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3 years ago

10

19]

1 answer:

FinnZ [79.3K]3 years ago

4 0

Answer:

oh

Step-by-step explanation:

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rodikova [14]

Answer:

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Step-by-step explanation:

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1 year ago

How do you solve: f(x) = -x2e-x<br> +2xe-x , finding the zero's of f.

Maksim231197 [3]

Answer:

0 and 2

Step-by-step explanation:

$f(x) = -x^2e^{-x}+2xe^{-x}$

To find zeros set f(x)=0 and solve for x

$0 = -x^2e^{-x}+2xe^{-x}$

$0 = -e^{-x}(x^2-2x)$

now factor out x

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$x=0$

$-e^{-x}=0$ no solution for x

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3 years ago

True or false when we carry out a chai square test of Independence the alternate hypothesis states that the two relevant classif

Anna35 [415]

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Step-by-step explanation:

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2 years ago

Tan(x+y)=x. (2 3) , what is dy/dx

horsena [70]

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Step-by-step explanation:

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