Question

Write a calculate_sq_inches_of_good_pizza function that accepts the diameter of a pizza and returns the area of the pizza minus 1 inch at the edge.

Answer 1

Answer:

#include <iostream>

using namespace std;

float calculate_sq_inches_of_good_pizza(float diameter) {

   float radius= diameter/2;    

   float pi=3.14;

   float area;        

   area = pi*(radius*radius );

   return area;

}

int main() {  

   float d;

   cout<<"enter the diameter of pizza"<<endl;

   cin>>d>>endl;

   float area_of_pizza = calculate_sq_inches_of_good_pizza();

   return 0;

}

Explanation:

Above program is written in C++ language which has function namely    float calculate_sq_inches_of_good_pizza(float diameter). This will calculate area of pizza from  given diameter and return it to main() function.

As we know pizza is circle and area of circle is equal to:

Area = π * radius*radius

π =pi=3.14

and we have calculated radius from given diameter

radius = diameter/2;

If you only want function not whole program than ignore main () function and only consider float calculate_sq_inches_of_good_pizza(float diameter) function which is in ITALIC notation.