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3 years ago

6

Bro I’m lazy and I don’t wanna do it if someone can do it it would mean a lot

2 answers:

Rus_ich [418]3 years ago

8 0

Answer:

I feel ya. It's the second one. Have a nice day.

Step-by-step explanation:

NARA [144]3 years ago

3 0

Answer:

Option 2.

Step-by-step explanation:

X is a number greater than the equality. Therefore the arrow will go to the bigger side. It also is not equal to the equality hence the cirle is open.

You might be interested in

Enter a recursive rule for the geometric sequence. 6, −18, 54, −162, ...

svlad2 [7]

Answer:

The required recursive formula is:

$a_n=(-3)\times a_{n-1}$

Step-by-step explanation:

We are given a geometric sequence as:

6,-18,54,-162,.....

Clearly after looking at different terms of the sequence we could observe that the sequence is an geometric progression (G.P.) with common ratio= -3 denoted by r.

Let $a_n$ represents the nth term of the sequence.

This means that:

$a_1=6, a_2=-18, a_3=54, a_4=-162,......$

As the common ratio is -3.

so,

$a_1=6\\\\a_2=-18=(-3)\times a_1\\\\a_3=54=(-3)\times a_2\\\\.\\.\\.\\.\\.\\.\\.\\.\\.a_n=(-3)\times a_{n-1}$

Hence, the required recursive formula for the geometric sequence is:

$a_n=(-3)\times a_{n-1}$

5 0

3 years ago

Sylvester wants his hand to have a sum of -1. Click on three cards that Sylvester could choose. . -9 , 5 , -7, 1 , 4 , -2 , 3

irina1246 [14]

5,3 and -9 equal -1..

8 0

3 years ago

The ratio of girls to boys in Mr. Smith's homeroom is 3:4. The ratio in Mr. Smith's homeroom to students in the whole 7th grade

Leno4ka [110]

3:4 = G:B

1:5 = Mr. Smith's class: 7th Grade

2:7= 7th: Middle school

12 girls = 3 units

1 unit = 12/3= 4

Boys = 4x4= 16

<em>Whole class = 28 students</em>

Class : Grade = 1:5 <em> 7 = number of units in Mr. Smith's class</em>

28 = 1 unit

5 units= 28x5= 140 <em>There are 140 kids in the grade</em>

140 = 2 units

1 unit = 140/2= 70

70x7=490

<u><em>There are 490 students in the whole grade</em></u>

6 0

3 years ago

Write the equation of the line that contains the points (4, −7) and (1, 5). The slope of the line that contains the points (4, −

deff fn [24]

Slope = (5+7)/(1-4) = 12/-3 = -4

slope = -4

y = mx + b
-7 = -4(4) + b
-7 = -16 + b
b = 9

equation
y = -4x + 9

4 0

3 years ago

Read 2 more answers

Find all values of the angle θ (in radians, with 0 ≤ θ < 2π) for which the matrix a = cos θ −sin θ sin θ cos θ has real eigen

harina [27]

The matrix

$A=\begin{bmatrix}\cos\theta&-\sin\theta\\\sin\theta&\cos\theta\end{bmatrix}$

has eigenvalues $\lambda$ such that

$\det(A-\lambda I)=\begin{vmatrix}\cos\theta-\lambda&-\sin\theta\\\sin\theta&\cos\theta-\lambda\end{vmatrix}=0$

$(\cos\theta-\lambda)^2+\sin^2\theta=0$

$(\cos\theta-\lambda)^2=-\sin^2\theta$

$\cos\theta-\lambda=\pm\sqrt{-\sin^2\theta}$

$\lambda=\cos\theta\pm\sqrt{-\sin^2\theta}$

$\sin^2\theta\ge0$ for all values of $\theta$ , so we need to have $\sin\theta=0$ in order for $\lambda$ to be real-valued. This happens for

$\sin\theta=0\implies\theta=n\pi$

where $n$ is any integer, and over the given interval we have $\theta=0$ and $\theta=\pi$ .

4 0

3 years ago