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BaLLatris [955]
3 years ago
15

Peter and Mary take turns throwing one dart at the dartboard. Peterhits the bulls eye with probabilitypand Mary hits the bullsey

e with probabilityr.Whoever hits the bullseye first wins. Suppose Peter throws the first dart.(a) What is the probability that Mary wins
Mathematics
1 answer:
EastWind [94]3 years ago
6 0

Answer:

P(Mary) = (1 - p) * r

Step-by-step explanation:

Given

p \to Peter hits

r \to Mary hits

Required

The probability that Mary wins

From the question, we understand that Peter throws the first.

If Mary is to win, then Peter has to lose his throw

Using the complement rule, the probability that Peter misses is:

p' = 1 - p

So, the probability that Mary wins is:

P(Mary) = p' * r

This gives:

P(Mary) = (1 - p) * r

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Venn diagram ( attached image )
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Assessing the given Venn diagram and the data related to it, we can answer the required question:

Q1. How many people were surveyed = 86.

Q2. What is the probability that a customer chosen at random:

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b) takes both salt and vinegar P(S ∩ V) = 13/85.

c) takes salt or vinegar or both P(S ∪ V) = 66/85.

The number of people who take salt chips n(S) = 46.

The number of people who take vinegar chips n(V) = 33.

The number of people who takes both n(S ∩ V) = 13.

The number of people who take neither n((S ∪ V)') = 19.

Therefore, the total number of people surveyed n(U) = n(S) + n(V) - n(S ∩ V) + n((S ∪ V)') = 46 + 33 - 13 + 19 = 85.

The number of people who takes salt or vinegar or both n(S ∪ V) = n(U) - n((S ∪ V)') = 85 - 19 = 66.

The probability that a customer chosen at random takes salt P(S) = n(S)/n(U) = 46/85.

The probability that a customer chosen at random takes both salt and vinegar P(S ∩ V) = n(S ∩ V)/n(U) = 13/85.

The probability that a customer chosen at random takes salt or vinegar or both P(S ∪ V) = n(S ∪ V)/n(U) = 66/85.

Learn more about Venn Diagrams at

brainly.com/question/24713052

#SPJ10

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