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BaLLatris [955]
3 years ago
15

Peter and Mary take turns throwing one dart at the dartboard. Peterhits the bulls eye with probabilitypand Mary hits the bullsey

e with probabilityr.Whoever hits the bullseye first wins. Suppose Peter throws the first dart.(a) What is the probability that Mary wins
Mathematics
1 answer:
EastWind [94]3 years ago
6 0

Answer:

P(Mary) = (1 - p) * r

Step-by-step explanation:

Given

p \to Peter hits

r \to Mary hits

Required

The probability that Mary wins

From the question, we understand that Peter throws the first.

If Mary is to win, then Peter has to lose his throw

Using the complement rule, the probability that Peter misses is:

p' = 1 - p

So, the probability that Mary wins is:

P(Mary) = p' * r

This gives:

P(Mary) = (1 - p) * r

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92.4 is 150% of what number?
Ad libitum [116K]
1. We assume, that the number 92.4 is 100% - because it's the output value of the task. 
<span>2. We assume, that x is the value we are looking for. </span>
<span>3. If 92.4 is 100%, so we can write it down as 92.4=100%. </span>
<span>4. We know, that x is 150% of the output value, so we can write it down as x=150%. </span>
5. Now we have two simple equations:
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7. Solution for what is 150% of 92.4

92.4/x=100/150
<span>(92.4/x)*x=(100/150)*x       - </span>we multiply both sides of the equation by x
<span>92.4=0.666666666667*x       - </span>we divide both sides of the equation by (0.666666666667) to get x
<span>92.4/0.666666666667=x </span>
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<span>now we have: </span>
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