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Dmitry_Shevchenko [17]
3 years ago
5

Enter the number of complex zeros for the polynomial function in the box.

Mathematics
1 answer:
Monica [59]3 years ago
6 0

Answer:

The answer is 3.

Step-by-step explanation:

I took the quiz.

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Which of the following would best be solved using factoring the difference of squares? 2² + 3x - 10 = 0 O 3r² + 12x = 8 2³ +52²
IgorC [24]

Given: Different equations

To Determine: Which would be best solved using difference of two squares

Solution

The factorization of a difference of two squares is given below

a^2-b^2=(a-b)(a+b)

Let us examine each of the given equation

\begin{gathered} x^2+3x-10=0 \\ x^2-2x+5x-10=0 \\ x(x-2)+5(x-2)=0 \\ (x-2)(x+5)=0 \end{gathered}\begin{gathered} 3x^2+12x=8 \\ 3x^2+12x-8=0 \end{gathered}\begin{gathered} x^3+5x^2-9x-45=0 \\ x^2(x+5)-9(x+5)=0 \\ (x+5)(x^2-9)=0 \\ x^2-9=x^2-3^2=(x+3)(x-3) \\ Therefore \\ (x+5)(x+3)(x-3)=0 \end{gathered}\begin{gathered} x^2-25=0 \\ x^2-5^2=0 \\ (x+5)(x-5)=0 \end{gathered}

From the above,

\begin{gathered} x^3+5x^2-9x-45=0 \\ AND \\ x^2-25=0 \end{gathered}

The two equation above can be solved by difference of two square, but the equation below is the easiest solved using differnce of two square

x² - 25 = 0

3 0
1 year ago
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mojhsa [17]
I- please ask a question. This is not a question
7 0
3 years ago
Read 2 more answers
Hellllllllllllllp. this scale drawing of a desktop
Kruka [31]
So the since the length of the longer side is 45inches we know that the longer table is 5 times as larger than the small desktop. And we know 6 x 5 = 30.
So 45x30= 1,350 so the answer is 1,350 square inches! :)
6 0
3 years ago
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5.7y-5.2=y/2.5 how to solve
11Alexandr11 [23.1K]

5.7y-5.2=y/2.5

Add 5.2 to both sides:

5.7y = y/2.5 + 5.2

y/2.5 = 0.4y

5.7y = 0.4y + 5.2

Subtract 0.4y from both sides:

5.3y = 5.2

Divide both sides by 5.3:

y = 5.2/5.3

y = 0.98113

3 0
2 years ago
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What is 6/7 divided by 3?<br> 1 , 2 , 3 , 4 , 5 , 6 , 7 , 8 , 9 , 10
3241004551 [841]

Answer:

Exact Form:

2/7

Decimal Form:

0.285714 (Terminating)

5 0
3 years ago
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