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3 years ago

Please help it’s due tonight. Your help will be greatly appreciated.There is also a graph. WILL PUT YOU AS BRAINLY!!!!!!

Mathematics

1 answer:

chubhunter [2.5K]3 years ago

5 0

Answer: see below

Step-by-step explanation:

The shape is a trapezoid

Base 1 (BH) is 10

Base 2 (QA) is 14

Height is 5

Area

$A=\frac{base_{1} +base_{2} }{2} h$

$A=\frac{10+14}{2} *5\\A=12*5\\A=60$

Find distance between QB and HA

$D=\sqrt{(x_{2} -x_{1}) ^{2}+(y_{2}-y_{1}) ^{2}$

Q( -4,4) B (-2,9)

$D=\sqrt{(-2--4)^{2}+(9-4)^{2} } \\D=\sqrt{2^{2} +5^{2} } \\D=\sqrt{29}$

Perimeter

$P=10+14+2\sqrt{29} \\P=24 +2\sqrt{29} \\P= 24+10.77\\P=34.77$

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2. Bend the b-x piece to form a triangle with side (b-x)/3

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so $r= \frac{x}{2 \pi }$

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$(\frac{ \sqrt{3} }{18}+\frac{1}{2 \pi }) x=\frac{ \sqrt{3} }{18}b$

$x= \frac{\frac{ \sqrt{3} }{18}b}{(\frac{ \sqrt{3} }{18}+\frac{1}{2 \pi }) }$

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