Answer:
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The range is the ouutput from inputing the input
basically
25=k²+2k+1 and 64=k²+2k+1
the values that satisfy both equations (not at the same tim) are the valuess that are the domain
solve each
25=k²+2k+1
minus 25 both sides (or recognize the perfect square trinomial, but anyway)
0=k²+2k-24
factor
0=(k+6)(k-4)
set to zero
k+6=0
k=-6
k-4=0
k=4
k=-6 or 4
64=k²+2k+1
minus 64 both sides
0=k²+2k-63
facor
0=(k-7)(k+9)
set to zer
k-7=0
k=7
k+9=0
k=-9
k=-9 or 7
so the domain has the numbers
-9,-6,4,7
it seems we only want the positive square roots so
answer is {4,7} is the domain
Answer:
Step-by-step explanation:
let the number of dimes=x
and number of quarters=y
x=2y
0.10 x+0.25 y=2.25
or 10x+25y=225
divide by 5
2x+5y=45
2 ×2y+5y=45
4y+5y=45
9y=45
y=45/9=5
x=2y=2×5=10
Hence dimes=10
quarters=5
Hey there!
Let's first simplify this expression using our rules of exponents.
We know that:
1)

And:
2)

Finally:
3)

One more:
4)

Now, we can simplify the top. Using our rule number 1<em />, we know we can just multiply the exponents to get 7^12. On the bottom, using our rule number 2, we know we can add out exponents to also get 7^12.
Without even simplifying the powers, we know that everything over itself if one. Therefore, in our answer choices, we're looking for everything not equal to one.
For the 7^12/7^12, we know that's what we just got so it equals one. For the 1, well, one equals one. For the next one, referring to our last rule, 4, anything to the power of 0 equals one, therefore that's also equal to one.
Now for our final answer choice. If we take another look at rule number 3, we know we have to subtract the exponent at the bottom from the one at the top because the exponents have the same base. That gives us 7^-24, and that surely does not equal one.
Therefore, your answer is:

Hope this helps!

It can be expressed as a fraction with integer numerator and denominator, so it's a rational number.