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marin [14]
3 years ago
8

8x + 4 = 4(2x – 3) n

Mathematics
1 answer:
miss Akunina [59]3 years ago
4 0

Answer:

it should be positive 16

Step-by-step explanation:

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Equation for dividing example 25 divided by 5
Dafna11 [192]

Answer: Example: 15 ÷ 5

Step-by-step explanation:

6 0
3 years ago
The volume of a pyramid that fits exactly inside a cube is 49 cubic feet. what is the volume of the cube?
8090 [49]
The volume of a pyramid is 1/3 the volume of the cube mentioned in the question since it fits exactly inside it. So multiply 49*3 = 147 cubic feet
6 0
3 years ago
Read 2 more answers
X= -1/5; f(x) = (25/2)x + (-91/2) =
Diano4ka-milaya [45]

Answer:

Write the problem as a mathematical expression.

X=−1/5; f(x)=(25/2)x+(−91/2)

Replace the variable x with x=−1/5 in the expression.

f(−1/5)=(25/2)(−1/5)−91/2

Simplify the result.

−48

Step-by-step explanation:

4 0
3 years ago
2x+5y=60 <br> 2x-5y=-20<br><br><br> Please show work!
sergejj [24]
 (2x+5y=60)
- (2x-5y=-20)
-------------------
10y=80
y=8 


2x+5(8)=60
2x+40=60 
2x=20
x=10


8 0
4 years ago
In a widget factory, machines A, B, and C manufacture, respectively, 20, 30, and 50 percent of the total. Of their output 6, 3,
steposvetlana [31]

Answer:

38.71% probability it was manufactured by machine A.

29.03% probability it was manufactured by machine B.

32.26% probability it was manufactured by machine C.

Step-by-step explanation:

We have these following probabilities:

A 20% probability that the chip was fabricated by machine A.

A 30% probability that the chip was fabricated by machine B.

A 50% probability that the chip was fabricated by machine C.

A 6% probability that a chip fabricated by machine A was defective.

A 3% probability that a chip fabricated by machine B was defective.

A 2% probability that a chip fabricated by machine C was defective.

The question can be formulated as:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

P = \frac{P(B).P(A/B)}{P(A)}

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

What are the probabilities that it was manufactured by machines A, B, and C?

Machine A

What is the probability that the widget was manufactures by machine A, given that it is defective?

P(B) is the probability that it was manufactures by machine A. So P(B) = 0.20

P(A/B) is the probability that a widget is defective, given that it is manufactured by machine A. So P(A/B) = 0.06

P(A) is the probability that a widget is defective. This is the sum of 6% of 20%, 3% of 30% and 2% of 50%. So

P(A) = 0.06*0.20 + 0.03*0.30 + 0.02*0.5 = 0.031

So

P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.2*0.06}{0.031} = 0.3871

38.71% probability it was manufactured by machine A.

Machine B

What is the probability that the widget was manufactures by machine B, given that it is defective?

P(B) is the probability that it was manufactures by machine B. So P(B) = 0.30

P(A/B) is the probability that a widget is defective, given that it is manufactured by machine B. So P(A/B) = 0.03

P(A) = 0.06*0.20 + 0.03*0.30 + 0.02*0.5 = 0.031

So

P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.3*0.03}{0.031} = 0.2903

29.03% probability it was manufactured by machine B.

Machine C

What is the probability that the widget was manufactures by machine C, given that it is defective?

P(B) is the probability that it was manufactures by machine C. So P(B) = 0.50

P(A/B) is the probability that a widget is defective, given that it is manufactured by machine C. So P(A/B) = 0.02

P(A) = 0.06*0.20 + 0.03*0.30 + 0.02*0.5 = 0.031

So

P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.5*0.02}{0.031} = 0.3226

32.26% probability it was manufactured by machine C.

6 0
3 years ago
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