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3 years ago

Which ratio is equivalent to 8/6? A. 3/24 B. 24/32 C. 32/24 D. 24/3

Mathematics

2 answers:

Ber [7]3 years ago

5 0

Answer:

Answer: C. 32/24

Step-by-step explanation:

8 x 4 and 6 x 4

Maru [420]3 years ago

3 0

Answer:

Step-by-step explanation:

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1. An AP Statistics class starts a project to estimate the average number of hours a student at their high school sleeps per nig

Vladimir [108]

Answer:

Option E

Step-by-step explanation:

This survey will not be reliable as it is chosen for convenience; the first 120 students to arrive in school on a particular morning and this collection of individuals may not be a representative of the population. The study may become biased because it does not take into account the latecomers among the students which might have been changed the study from systematically favoring certain outcomes.

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3 years ago

GCF of 20 and another number is four. Which of these could be the other number

Nina [5.8K]

Answer:

Step-by-step explanation:

4 x 9=32

3 0

3 years ago

Read 2 more answers

Isamasonip invested $2.000 in

alexgriva [62]

Answer:

Compound Interest= $3440

Final Amount= $5440

Step-by-step explanation:

Compound Interest's formula= P(1+r/100)^n

where P is Principal, r is Rate then n is Years

So in this case,,2000(1+.72)^1 = $3440

Hence, Total Amount = Principal+Interest

therefore T.A= $2000+$3440

T.A=$5440

Thanks... Subjected to Review

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3 years ago

Solve 4x + 5 = x + 26

prohojiy [21]

Answer:

Step-by-step explanation: 7

Subtract 5 on both sides to get 4x = x + 21

then, subtract x from 4x and x is 1, so 3x = 21 then divide by 3 on both sides

8 0

3 years ago

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A ship leaves port at noon and has a bearing of S29oW. The ship sails at 20 knots. How many nautical miles south and how many na

ira [324]

Answer:

Approximately $58.2\; \text{nautical miles}$ (assuming that the bearing is ${\rm S$29^{\circ}$W}$ .)

Step-by-step explanation:

Let $v$ denote the speed of the ship, and let $t$ denote the duration of the trip. The magnitude of the displacement of this ship would be $v\, t$ .

Refer to the diagram attached. The direction ${\rm S$29^{\circ}$W}$ means $29^{\circ}$ west of south. Thus, start with the south direction and turn towards west (clockwise) by $29^{\circ}$ to find the direction of the displacement of the ship.

The hypothenuse of the right triangle in this diagram represents the displacement of the ship, with a length of $v\, t$ . The dashed horizontal line segment represents the distance that the ship has travelled to the west (which this question is asking for.) The angle opposite to that line segment is exactly $29^{\circ}$ .

Since the hypotenuse is of length $v\, t$ , the dashed line segment opposite to the $\theta = 29^{\circ}$ vertex would have a length of:

$\begin{aligned}& \text{opposite (to $\theta$)} \\ =\; & \text{hypotenuse} \times \frac{\text{opposite (to $\theta$)}}{\text{hypotenuse}} \\ =\; & \text{hypotenuse} \times \sin (\theta) \\ =\; & v\, t \, \sin(\theta) \\ =\; & v\, t\, \sin(29^{\circ})\end{aligned}$ .

Substitute in $\begin{aligned} v &= 20\; \frac{\text{nautical mile}}{\text{hour}}\end{aligned}$ and $t = 6\; \text{hour}$ :

$\begin{aligned} & v\, t\, \sin(29^{\circ}) \\ =\; & 20\; \frac{\text{nautical mile}}{\text{hour}} \times 6\; \text{hour} \times \sin(29^{\circ}) \\ \approx\; & 58.2\; \text{nautical mile}\end{aligned}$ .

7 0

2 years ago