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3 years ago

10

Find the angle measures in each regular polygon

1 answer:

erma4kov [3.2K]3 years ago

5 0

Answer:

Step-by-step explanation:

jason jumped off of a cliff into the ocean in Acapulco while vacationing, ... second, then its height h after t seconds is given by the equation h(t) = -1672 ... 3. A rocket is launched from atop a 101 - foot cliff with an initial velocity of 116 ft/s. a. ... formula h(t) = -1612 + vt+s to find how long it will take for the ball to hit the ground.

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Nelson middle school raise $19,950 on ticket sales for it's carnival fundraiser last year at $15 per ticket. If the school sells

Snowcat [4.5K]

19950/15=1330 they sold 1,330 tickets last year
1330*20=26600
if they sold the same amount of tickets as they did last year for $20 they would have 26,600 in sales.

3 0

4 years ago

Select all the correct answers. Select all the Expressions that are equivalent to the polynomial below. (3x-7)(2x+8)

Leno4ka [110]

Answer:

6x ² - 10x - 56

Step-by-step explanation:

(3x -7) (2x +8)

To expand this, each term in the first bracket would multiply the other bracket.

3x(2x +8) -7( 2x + 8)

6x ² + 24x - 14x - 56

6x ² + 10x - 56

I hope this was helpful, Please mark as brainliest²

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4 years ago

Read 2 more answers

Which figure is a radius of F? worth 20 points

Makovka662 [10]

Answer:

FD

Step-by-step explanation:

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3 years ago

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fiasKO [112]

Answer:

Umm here BUT DONT JUDGE I HAD TO DO THIS ON MICROSOFT PAINT WITH A MOUSE AND IT WAS NOT FUN slope= 3/4

Step-by-step explanation:

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2 years ago

Find the value of tan30+cot30+sin60

Aliun [14]

Hello!

This is a problem about relating values of the Unit Circle.

First, we need to figure out the specific "points" of each angle measure of 30 and 60.

For the angle measure 30, the point will be $(\frac{\sqrt{3}}{2},\frac{1}{2})$ .

For the angle measure 60, the point will be $(\frac{1}{2},\frac{\sqrt{3}}{2})$ .

The tangent value of a point will be its $y$ value over its $x$ value.

$\frac{\frac{1}{2}}{\frac{\sqrt{3}}{2}}=\frac{1}{2}*\frac{2}{\sqrt{3}}=\frac{1}{\sqrt{3}}=\frac{\sqrt{3}}{3}$

The cotangent value of a point will be the reciprocal of the tangent value, which we found previously.

$\frac{3}{\sqrt{3}}=\frac{3\sqrt{3}}{3}=\sqrt{3}$

The sine value of a point will be the $y$ value of the point.

$\frac{\sqrt{3}}{2}$

So the values we have so far are $\frac{\sqrt{3}}{3}+\sqrt{3}+\frac{\sqrt{3}}{2}$

Now we have to find the LCD to add these together, which in this case would be 6.

$\frac{2\sqrt{3}}{6}+\frac{6\sqrt{3}}{6}+\frac{3\sqrt{3}}{6}$

Which adds up to $\frac{11\sqrt{3}}{6}$ , which is in simplest radical form.

Hope this helps!

8 0

3 years ago