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Bad White [126]
3 years ago
6

A=34.5. B=29.04. C= 204.7 D= 18.83

Mathematics
1 answer:
ahrayia [7]3 years ago
5 0

The answer is B.) 29.04

you find c and then add it to a and b

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The diameters of ball bearings are distributed normally. The mean diameter is 83 millimeters and the standard deviation is 3 mil
Alenkinab [10]

Answer:

0.2514 = 25.14% probability that the diameter of a selected bearing is greater than 85 millimeters.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

\mu = 83, \sigma = 3

Find the probability that the diameter of a selected bearing is greater than 85 millimeters.

This is 1 subtracted by the pvalue of Z when X = 85. Then

Z = \frac{X - \mu}{\sigma}

Z = \frac{85 - 83}{3}

Z = 0.67

Z = 0.67 has a pvalue of 0.7486.

1 - 0.7486 = 0.2514

0.2514 = 25.14% probability that the diameter of a selected bearing is greater than 85 millimeters.

7 0
3 years ago
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