Answer:
1/2 =0.5
1/2+0i=io+1/2
1/2i=1/2i
1+2i
=1+2i
Step-by-step explanation:
Answer: The equation of the perpendicular line intersects the point (-5,1) is y=x+6[/tex]
Step-by-step explanation:
step1:-
The standard form of slope - intercept form y=m x+c
Here m is called slope of the given line
C is called the y- intercept of the given line
Given equation of the straight line y=-x+1
comparing the slope - intercept form y=m x+c
here m= -1 and c=1
step2:-
The equation of the perpendicular line is
} =\frac{-1}{m} (x-x_{1} )[/tex]
substitute m = -1 and c =1 values in equation



step3:- The equation of the perpendicular line intersects the point (-5,1) is
y=x+6[/tex]
<u>conclusion</u><u>:</u>-
The equation of the perpendicular line is
y=x+6[/tex]
Answer:
The equation of the line in slope-intercept form is:
y = x + 4
Step-by-step explanation:
The slope-intercept form of the line equation

where
Given the points on the line graph
Determining the slope between (0, 4) and (1, 5)
(x₁, y₁) = (0, 4)
(x₂, y₂) = (1, 5)
Using the formula
Slope = m = [y₂ - y₁] / [x₂ - x₁]
= [5 - 4] / [1 - 0]
= 1 / 1
= 1
Thus, the slope of the line = m = 1
We know that the value of the y-intercept can be determined by setting x = 0 and determining the corresponding value of y.
From the graph, it is clear
at x = 0, y = 4
Thus, the y-intercept b = 4
now substituting b = 4 and m = 1 in the slope-intercept form
y = mx + b
y = (1)x + 4
y = x + 4
Therefore, the the equation of the line in slope-intercept form is:
y = x + 4
(x + 2y) ^2
(x + 2y) (x + 2y)
x^2 + 2xy + 2xy + 4y^2
= x^2 + 4xy + 4y^2