Question

Trig question ———————

Answer 1

Answer:

1) $\cos(A) = 0.948(appx)$

2) $\sin(A) = 0.316(appx)$

3) $\tan(A) = 0.333(appx)$

Step-by-step explanation:

Using Pythagorean theorem ,

Hypotenuse =

$\sqrt{ {6}^{2} + {2}^{2} } = \sqrt{36 + 4} = \sqrt{40} = 2 \sqrt{10}$

We know that

• $\sin( \alpha ) = \frac{side \: opposite \: to \: \alpha }{hypotenuse \: of \: triangle}$
• $\cos( \alpha ) = \frac{side \: adjacent \: to \: \alpha }{hypotenuse \: of \: triangle}$
• $\tan( \alpha ) = \frac{side \: opposite \: to \: \alpha }{side \: adjacent \: to \: \alpha }$

Where $\ alpha$ is an angle of tge triangle.

In the triangle given above , $\ alpha = angle \: A$ . So,

1) $\cos(A) = \frac{6}{2 \sqrt{10} } = \frac{3}{ \sqrt{10} } = 0.948(appx)$

2) $\sin(A) = \frac{2}{2 \sqrt{10} } = \frac{1}{ \sqrt{10} } = 0.316(appx)$

3) $\tan(A) = \frac{2}{6} = \frac{1}{3} = 0.333(appx)$