Please help me, due tomorrow!
1 answer:
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Answer:
The expectation the instructor to send each day
E(X) = 3.65
Step-by-step explanation:
Given data x : 0 1 2 3 4 5
P(X=x) : 0.05 0.05 0.1 0.1 0.4 0.3
The given data satisfy the two conditions
I) Given all probabilities are p₁(x) ≥0
ii) sum of all probabilities is equal to one
0.05 + 0.05 + 0.1 + 0.1 + 0.4 +0.3 =1
Therefore given data is discrete probability distribution
<u>Expectation</u> :-
suppose a random variable X assumes the values with respective probabilities
, then the Expectation or Expected value of X , denoted by E(X) = ∑pi xi
on simplification, we get
E(X) = 3.65