Please help me, due tomorrow!

When multiplying a number by 10, move the decimal to the right. When multiplying a number by 0.1, move the decimal to the left.

ki77a [65]

Answer: 0.01 x 10 = .1

it moved ten spaces up or in simpler terms the decimal move one space to the right because the number is getting bigger.

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

WILL MARK BRAINLIST PLEASE HELP THIS IS DUE SOON

nikitadnepr [17]

Answer:

C

Step-by-step explanation:

180

3 0

3 years ago

Can someone answer these??

hoa [83]

Use the substitution method

Answers :

g(x)= -3x+1

a. g(10)= -3(10)+1

Mutiply first = -30

-30+1= -29

g(10)= -29

b. g(-2)= -3(-2)+1

Negative sign and negative sign = positive sign

-3(-2)= 6

6+1= 7

g(-2)= 7

a.

f(x)=x^2+7

f(3)= 3^ 2+7

3*3 because of the exponent. 3*3= 9

9+7= 16

f(3)= 16

d.

f(a)= a^2+7

a*a= a^2

a^2+7

f(a)= a^2+7

7 0

3 years ago

Nia's bag weighs 5-sixths of the maximum weight allowed for bags on an airplane. The maximum weight allowed is 45 pounds. What i

scZoUnD [109]

Answer:

54

Step-by-step explanation:

copy dot flip 45/1 divided by 5/6

first copy dot flip so 45/1 then multiply and flip 5/6 so it looks like this

45/1 x 6/5= 270/5 then you need to see how many time 5 goes in 270 which is 54 and thats you anwser hope this helps sorry if im wrong

4 0

3 years ago

The probability that your call to a service line is answered in less than 30 seconds is 0.75. Assume that your calls are indepen

vfiekz [6]

Answer:

a) 0.2581

b) 0.4148

c) 17

Step-by-step explanation:

For each call, there are only two possible outcomes. Either they are answered in less than 30 seconds. Or they are not. The probabilities for each call are independent. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem we have that:

$p = 0.75$

a. If you call 12 times, what is the probability that exactly 9 of your calls are answered within 30 seconds? Round your answer to four decimal places (e.g. 98.7654).

This is $P(X = 9)$ when $n = 12$ . So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 9) = C_{12,9}.(0.75)^{9}.(0.25)^{3} = 0.2581$

b. If you call 20 times, what is the probability that at least 16 calls are answered in less than 30 seconds? Round your answer to four decimal places (e.g. 98.7654).

This is $P(X \geq 16)$ when $n = 20$