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Roman55 [17]
3 years ago
5

Fale runs each lap in 6 minutes. He will run at most 30 minutes today. What are the possible numbers of laps he will run today?

Mathematics
2 answers:
fgiga [73]3 years ago
7 0
The answer is 5. 30 divide 6=n. In the question it said Fale will run 30 minutes today, and if he can run a lap in 6 minute, you will have to divide to get the answer, which is n or 5.
Gala2k [10]3 years ago
3 0

Answer:

n ≤ 5

Step-by-step explanation:

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A school requires that 1 adult accompany every 8 students on a field trip. How many adults are needed to accompany 32 students?
mrs_skeptik [129]

Answer: 4 adults are needed to accompany 32 students.

Step-by-step explanation:

Given: School requires 1 adult to accompany every 8 students on a field trip.

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Hence, 4 adults are needed to accompany 32 students.

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How long is 10 percentage of 60 minutes?
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Musya8 [376]

Let the width of room be =x mtrs

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andrey2020 [161]
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3 0
3 years ago
Find the remaining trigonometric functions of θ based on the given information.csc θ = 257 and cos θ < 0
katrin [286]
Cos(<span>θ) < 0, so we know it would be in Quadrant 2 or 3
then csc(</span>θ) = 257, but csc(θ) = \frac{1}{sin(θ)} = 257
==> sin(<span>θ) = \frac{1}{257}
it is positive, so now we can determine that is in Quadrant 2

sin(</span>θ) = opp./hyp both of opp and hyp are positive but adj suppose to negative because that way it leads the cos(<span>θ) < 0
</span>cos(<span>θ) = adj/hyp
</span>Pythereom to find the adj: 257^{2} -  1^{2}  = adj ==\ \textgreater \  adj  \sqrt{ 257^{2} -   1^{2} } ==\ \textgreater \  adj = 16 \sqrt{258}

cosθ = \frac{16 \sqrt{258} }{257} &#10;
tanθ = \frac{1}{16 \sqrt{258} }
cos<span>θ = </span>16 \sqrt{258}
6 0
3 years ago
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