Fale runs each lap in 6 minutes. He will run at most 30 minutes today. What are the possible numbers of laps he will run today?

2 answers:

7 0

The answer is 5. 30 divide 6=n. In the question it said Fale will run 30 minutes today, and if he can run a lap in 6 minute, you will have to divide to get the answer, which is n or 5.

Gala2k [10]2 years ago

3 0

Answer:

n ≤ 5

Step-by-step explanation:

You might be interested in

(2b/3)^4 simplify the expression

Vladimir [108]

Answer:

$\large\boxed{\left(\dfrac{2b}{3}\right)^4=\dfrac{16b^4}{81}}$

Step-by-step explanation:

$\left(\dfrac{2b}{3}\right)^4\qquad\text{use}\ \left(\dfrac{a}{b}\right)^n=\dfrac{a^n}{b^n}\ \text{and}\ (ab)^n=a^nb^n\\\\=\dfrac{2^4b^4}{3^4}=\dfrac{16b^4}{81}$

6 0

2 years ago

the difference between seven times one number and three times a second number is 25. The sum of twice the first and five times t

inysia [295]

$\left \{ {{7*x - 3*y=25} \atop {2*x + 5*y=95}} \right.$

$\left \{ {{7x - 3y=25}(I) \atop {2x + 5y=95}(II)} \right.$

$\left \{ {{7x - 3y=25}simplify*(5) \atop {2x + 5y=95}simplify*(3)} \right.$

$\left \{ {{35x - \diagup\!\!\!\! 15 y=125} \atop {6x + \diagup\!\!\!\! 15y=285}} \right.$

$\left \{ {{35x =125} \atop {6x =285}} \right.$

$41x = 410$

$\boxed{x=10}$

<span>Replace the value of "x" in the second equation (II) to find the value of "y", thus:
</span> $2x + 5y=95$
$2*(10)+5y = 95$
$20+5y=95$
$5y=95-20$
$5y=75$
$y = \frac{75}{5}$
$\boxed{y=15}$

The numbers (10,15)

5 0

2 years ago

Phase ________ of clinical testing is required by the FDA before drug approval and uses the greatest number of subjects.

finlep [7]

The answer isC. Phase 3 <span>of clinical testing is required by the FDA before drug approval and uses the greatest number of subjects.
</span>

5 0

3 years ago

e. 2y(y + 3)this is not a quiz it is an assignment that is due tomorrow and I Wil be grateful for anyhelp

Elena-2011 [213]

We need to multiply