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Romashka-Z-Leto [24]
3 years ago
5

Drag the phrases into the box to match each expression. 3/4x+1/2 ​ 3/4−1/2x ​ ​ 3/4−(x+1/2) ​ 20 pointss!!! i know i must be cra

zy!!!!!!!
Mathematics
1 answer:
fomenos3 years ago
6 0

Answer:

\frac{3}{4}x + \frac{1}{2} = One-half more than three-fourths of a number

\frac{3}{4}-\frac{1}{2}x = Three-fourths minus one-half of a number

\frac{3}{4}-(x+\frac{1}{2}) = three-fourths minus the sum of a number and one-half

Step-by-step explanation:

Suppose x be an unknown number.

∵ 3/4th of a number = \frac{3}{4}x

\frac{3}{4}x + \frac{1}{2} = One-half more than three-fourths of a number

Now, half of a number = \frac{1}{2}x

\frac{3}{4}-\frac{1}{2}x = Three-fourths minus one-half of a number

Sum of a number and one-half = x+\frac{1}{2}

\frac{3}{4}-(x+\frac{1}{2}) = three-fourths minus the sum of a number and one-half

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この質問は緒と面白いね

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3/64

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Graph the system of equation below on a piece of paper what is the solution y=x-1 and y=-2x+5
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We are given

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y=x-1

we can use formula

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Which equation has the solutions x = startfraction 5 plus-or-minus 2 startroot 7 endroot over 3 endfraction?
Shtirlitz [24]

The equation that has the solution x = \frac{5 \pm \sqrt{7}}{3} is 3x^2 - 10x + 6 = 0

<h3>How to determine the equation?</h3>

The solution is given as:

x = \frac{5 \pm \sqrt{7}}{3}

The solution to a quadratic equation is

x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}

By comparing both equations, we have:

-b = 5

b^2 - 4ac = 7

2a = 3

Solve for b in -b = 5

b = -5

Solve for a in 2a = 3

a = 1.5

Substitute values for a and b in b^2 - 4ac = 7

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Evaluate

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Subtract 25 from both sides

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Divide by - 6

c = 3

So, we have:

a = 1.5

b =  -5

c = 3

A quadratic equation is represented as:

ax^2 + bx + c = 0

So, we have:

1.5x^2 - 5x +3 = 0

Multiply through by 2

3x^2 - 10x + 6 = 0

Hence, the equation that has the solution x = \frac{5 \pm \sqrt{7}}{3} is 3x^2 - 10x + 6 = 0

Read more about quadratic equation at:

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